3 years ago

1. Find a 10 in the sequence given by an = -5 + 9(n − 1). 010 =

Mathematics

1 answer:

hjlf3 years ago

7 0

Answer:

Step-by-step explanation:

a10=-5+9(10-1)=-5+9×9=-5+81=76

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16: Find the coordinates of the foci and the vertices, the eccentricity, the length of the latus rectum of the Hyperbola y^2-16x

Morgarella [4.7K]

Answer:

Foci $(0,\pm\frac{\sqrt{17}}{4})$

Vertices: $(0,\pm 1)$

Eccentricity, e= $\frac{\sqrt{17}}{4}$

Length of latus rectum= $\frac{1}{8}$

Step-by-step explanation:

We are given that

$y^2-16x^2=1$

$y^2-\frac{x^2}{(\frac{1}{4})^2}=1$

The equation of hyperbola is along y-axis because y is positive

Compare the equation with

$y^2/a^2-x^2/b^2=1$ (Along y-axis)

We get

a=1, b=1/4

$a^2+b^2=c^2$

$1+\frac{1}{16}=c^2$

$\frac{16+1}{16}=c^2$

$c^2=\frac{17}{16}$

$c=\pm \frac{\sqrt{17}}{4}$

Therefore,

The coordinates of foci= $(0,\pm c)=(0,\pm\frac{\sqrt{17}}{4})$

The coordinated of vertices= $(0,\pm a)=(0,\pm 1)$

Eccentricity, e=c/a

$e=\frac{\frac{\sqrt{17}}{4}}{1}=\frac{\sqrt{17}}{4}$

Length of latus rectum= $\frac{2b^2}{a}$

Length of latus rectum= $2\times \frac{1}{16}=\frac{1}{8}$

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3 years ago

PLEASE HELP IOLL GIV EBRAINLIEST ANSWER!!

maks197457 [2]

Answer:

8 1/3 meters

Step-by-step explanation:

set up a proportion of corresponding sides:

TE/AY = JT/DY

25/AY = 18/6

cross-multiply:

18AY = 150

AY = 150/18 which is 8 1/3

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K= 2m-x/ x solve for x

Yakvenalex [24]

the answer is x = 2m/1+k

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Alona [7]

The correct answer is A

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3 years ago

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goblinko [34]

Answer:1. 12 ft sq.

2. 4 ft

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3 years ago

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