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3 years ago

Which two numbers are solutions of 2n - 15≤ = -3 ×║thank you║×

Mathematics

2 answers:

Valentin [98]3 years ago

7 0

The answer for which two numbers are solutions of 2n - 15≤ = -3

Is n≤ 6

Gelneren [198K]3 years ago

4 0

Answer:

n ≤ 6

Step-by-step explanation:

2n - 15 ≤ -3

Add 15 to both sides.

2n ≤ 12

Divide both sides by 2.

n ≤ 6

The solution of this inequality is any number less than or equal to 6. There is an infinite number of solutions. Since you are asked to pick two numbers that are solutions, I assume you have choices that were given. Look at the choices, and pick any number less than 6 and 6 itself if it is a choice.

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triangle abc is a right triangle. If AC = 4 and BC = 10, find AB. Leave your answer in simplest radical form.

kolbaska11 [484]

The answer is 2 radical 21

3 0

3 years ago

Round 2.349 to the hundredths place.

slava [35]

Answer: 2.35

Step-by-step explanation:

Tenths is first place after decimal, Hundredth is 2nd place after decimal.

Look towards next place (thousandths place)

Greater than 5? Round up

7 0

3 years ago

Read 2 more answers

Is x = 6 a solution to the equation 5(x – 3) = x + 13?

deff fn [24]

Answer:

x=6 is not a solution

Step-by-step explanation:

We can substitute 6 as x to find out:

5(6-3)=6+13

first, because of PEMDAS we'll do 6-3

5(3)=6+13

multiply 5 by 3 and add 6 and 13

15=19

Since the statement is not true, that means that x=6 is not a solution

Hope this helps!

8 0

3 years ago

Given: ABC is a right triangle with right angle C. AB = 14 centimeters and

Snezhnost [94]

Answer:7.6°

Step-by-step explanation:

Using sine formular

sinA/a =sinB/b

sin33/x = sin90/14

cross multiply

xsin90 = 14sin33

Divide bothside by sin90

x = 14sin33 / sin90

x= 7.6249 / 1

x = 7.6° to the nearest tenth.

4 0

3 years ago

What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$