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julsineya [31]
3 years ago
9

Solve with solution...no spam answers pls

Mathematics
2 answers:
Agata [3.3K]3 years ago
6 0
<span>Let's analyze Hannah's work, step-by-step, to see if she made any mistakes. 

</span>In Step 1, Hannah wrote \dfrac{d}{dx} (-3+8x) <span> as the sum of two separate derivatives </span>\dfrac{d}{dx}(-3)+ \dfrac{d}{dx} (8x) <span>using the </span><span>sum rule.
</span>
This step is perfectly fine. 

In Step 2, \dfrac{d}{dx}(8x) was kept as it is, and \dfrac{d}{dx}(-3) was rewritten as 0 using the constant rule.Indeed, according to the constant rule, the derivative of a constant number is equal to zero.

This step is perfectly fine. 

In Step 3, \dfrac{d}{dx} (8x)  was rewritten as \dfrac{d}{dx}(8) \dfrac{d}{dx}(x) supposedly using the constant multiple rule.

The problem is that according to the constant multiple rule, \dfrac{d}{dx}(8x)&#10; should be rewritten as 8 \dfrac{d}{dx}(x) and not as \dfrac{d}{dx}(8)\dfrac{d}{dx}(x).  

<span>Therefore, Hannah made a mistake in this step.</span>
djverab [1.8K]3 years ago
6 0
Step 3, it should have been 8*d/dx(x) which leads to

Step 4 = 8*1  which leads to

Step 5 = 8
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