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2 years ago

15

What is 166.44 dived by 4. PLEASE USE LONG DIVISION. The person who USES LONG DIVISION TO GET THE ANSWER GETS 10 points and brai

niest.

2 answers:

ArbitrLikvidat [17]2 years ago

5 0

Answer:

41.61

Step-by-step explanation:

Just divide.

$\begin{matrix}4\overline{|\smallspace166.44}\:\:\:\:\:\:\:\end{matrix}$

alex41 [277]2 years ago

3 0

Answer: We have the equation:

166.44 ÷ 4 = 41.610

Calculated to 3 decimal places.

0 4 1. 6 1 0

4 1 6 6. 4 4 0

− 0

1 6

− 1 6

0 6

− 4

2 4

− 2 4

0 4

− 4

0 0

− 0

0

Step-by-step explanation: hope this helps

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Choose the true statement. -2 < -3 -2 > -3 -2 = -3Choose the true statement.

Marrrta [24]

-2 < -3 (I think so anyway)

7 0

3 years ago

Please help, the question says what statement best describes the placement of the lines Carson Drew

blagie [28]

Answer:

Only line A is a well-placed line of best fit.

Step-by-step explanation:

I did this on Plato and got it correct.

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3 years ago

The function f(x)=-(x-3)^2 +9 can be used to represent the area of a rectangle with the perimeter of 12 units, as a function of

Ivenika [448]

Maximum area of the rectangle is $9cm^{2}$

<u>Explanation:</u>

<u></u>

Considering the dimensions to be in cm

$f(x) = -(x-3)^{2} +9\\f(x) = -(x^{2} +9 - 6x)+9\\f(x) = -x^{2} +6x\\f'(x) = -2x+6\\-2x+6 = 0\\2x=6\\x=3cm\\\\$

Putting the value of x = 3

$Perimeter = 2(x+b)\\12 = 2(3+b)\\6 = 3+b\\b= 3cm$

$Area of rectangle = x X b\\ = 3 X 3\\ = 9cm^{2}$

Therefore, maximum area of the rectangle is $9cm^{2}$

7 0

3 years ago

A manager needs to rope off a rectangular section for a private party. The length of the section must be 7.6 meters. The manager

Andrew [12]

Answer:

$W\leq 6.4\ m$

Step-by-step explanation:

we know that

The perimeter of a rectangle is equal to

$P=2(L+W)$

we know that

$L=7.6\ m$

$P\leq28\ m$

substitute

$2(7.6+W)\leq28$

solve for W

$(7.6+W)\leq14$

$W\leq14-7.6$

$W\leq 6.4\ m$

5 0

3 years ago

Find a power series for the function, centered at c. g(x) = 4x x2 2x − 3 , c = 0

BartSMP [9]

The power series for given function $g(x)=\frac{4x}{(x-1)(x+3)}$ is $g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$

For given question,

We have been given a function g(x) = 4x / (x² + 2x - 3)

We need to find a power series for the function, centered at c, for c = 0.

First we factorize the denominator of function g(x), we have:

$\Rightarrow g(x)=\frac{4x}{(x-1)(x+3)}$

We can write g(x) as,

$\Rightarrow g(x)=\frac{1}{x-1}+\frac{3}{x+3}\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1+\frac{x}{3} }\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1-(-\frac{x}{3} )}\\$

We know that, $\frac{1}{1-x}=\sum{_{n=0}^\infty}~{x^n}$ if |x| < 1

and $\frac{1}{1-(-\frac{x}{3} )}=\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n$ if $|\frac{x}{6}| < 1$

$\Rightarrow g(x)=-\sum{_{n=0}^\infty}~x^n+\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n\\$ if |x| < 1 and if $|\frac{x}{6}| < 1$

$\Rightarrow g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$ if |x| < 1

Therefore, the power series for given function $g(x)=\frac{4x}{(x-1)(x+3)}$ is $g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$

Learn more about the power series here:

brainly.com/question/11606956

#SPJ4

5 0

2 years ago