Answer:
B
Step-by-step explanation:
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The ticket price that would maximize the total revenue would be $ 23.
Given that a football team charges $ 30 per ticket and averages 20,000 people per game, and each person spend an average of $ 8 on concessions, and for every drop of $ 1 in price, the attendance rises by 800 people, to determine what ticket price should the team charge to maximize total revenue, the following calculation must be performed:
- 20,000 x 30 + 20,000 x 8 = 760,000
- 24,000 x 25 + 24,000 x 8 = 792,000
- 28,000 x 20 + 28,000 x 8 = 784,000
- 26,000 x 22.5 + 26,000 x 8 = 793,000
- 27,200 x 21 + 27,200 x 8 = 788,000
- 26,400 x 22 + 26,400 x 8 = 792,000
- 25,600 x 23 + 25,600 x 8 = 793,600
- 24,800 x 24 + 24,600 x 8 = 792,000
Therefore, the ticket price that would maximize the total revenue would be $ 23.
Learn more in brainly.com/question/7271015
Pretty sure its y > -6.2
This is because you subtract 4 from both sides and get y > -6.2
Please correct me if im wrong thx!
So first you have to move the -2 over to the opposite side.
8(9x-4)=3+2+2
Then you can simplify the right side
8(9x-4)=7
Then you distribute
8*9x=72x
8*-4=-32
so now you have...
72x-32=7
Then you move the 37 over
72x=39
Then you divide by 72 to isolate x
x=39/72 or x= 13/24 or <span>x=0.54167</span>
