Hello,
Assume Ax+By+Cz+D=0 the plane 's equation.
p=(0,0,0)==>A*0+B*0+C*0+D=0==>D=0
q=(0,1,0)==>A*0+B*1+C*0+0=0==>B=0
r=(1,2,3)==>A*1+0*2+C*3+0=0==>A=-3C
Let C=1==>A=-3
An equation of the plane is -3x+z=0
Answer:
x= 20 i think sorry if it's wrong⊙﹏⊙
Let's solve your equation step-by-step.
4x+2x−5=7x−1
Step 1: Simplify both sides of the equation.
4x+2x−5=7x−1
4x+2x+−5=7x+−1
(4x+2x)+(−5)=7x−1(Combine Like Terms)
6x+−5=7x−1
6x−5=7x−1
Step 2: Subtract 7x from both sides.
6x−5−7x=7x−1−7x
−x−5=−1
Step 3: Add 5 to both sides.
−x−5+5=−1+5
−x=4
Step 4: Divide both sides by -1.
−x
−1
=
4
−1
x=−4
Answer:
x=−4
i hope this helps you
If secant of theta =
<span>
<span>
<span>
1.0416666667
</span>
</span>
</span>
then
theta = 16.26 Degrees
cotangent of theta = 3.4286
