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salantis [7]
3 years ago
8

Multiply the binomials (x + 1)(-5x + 10) *

Mathematics
2 answers:
Leona [35]3 years ago
7 0
So i think here you would FOIL. so -5x^2+10x-5x+10 and then combine like terms :)
Assoli18 [71]3 years ago
5 0
(x+1)(-5x+10)
=-5x^2+10x-5x+10
= -5x^2+5x+10
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3^5 * 9^5 = 3^n<br> Find n please
Vladimir [108]

Answer:

In this equation n = 15

Step-by-step explanation:

In order to find this, we first must make each term a base 3. Since 9 is 3 squared, we can change it easily to base 3.

3^5 * 9^5 = 3^n

3^5 * (3^2)^5 = 3^n

3^5 * 3^10 = 3^n

3^15 = 3^n

Now that we have both in simple term of 3 raised to a power, we can eliminate the 3's and see that 15 = n

4 0
3 years ago
Find the error and explain what there is incorrectly. Then, solve the problem correctly.
frez [133]
The problem is that 7^2 is 7*7, and the same for 8^2. The right answer is the square root of 15, or 3.87
3 0
3 years ago
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Tina creates a dot plot using the match scores 3, 2, 4, 5, 2, 3, 1, 2, 1, and 5. Which of the following dot plots represents the
bogdanovich [222]
The answer is

B. A dot plot is shown with the title Match Scores. There are 2 dots over score 1, 3 dots over score 2, 2 dots over score 3, 1 dot over score 4, and 2 dots over score 5.

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7 0
3 years ago
How do you solve k/2+9=30
Mrrafil [7]
If you would like to solve the equation k / 2 + 9 = 30, you can calculate this using the following steps:

k / 2 + 9 = 30
k / 2 = 30 - 9 
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k = 21 * 2
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The result is 42.
4 0
3 years ago
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Determine the next step for solving the quadratic equation by completing the square.
Studentka2010 [4]

Answer:

The solutions are x=\frac{1+\sqrt{7}}{2} and x=\frac{1-\sqrt{7}}{2}

Step-by-step explanation:

we have

0=-2x^{2}+2x+3

Group terms that contain the same variable, and move the constant to the opposite side of the equation

-3=-2x^{2}+2x

Factor the leading coefficient

-3=-2(x^{2}-x)

Complete the square. Remember to balance the equation by adding the same constants to each side.

-3-0.5=-2(x^{2}-x+0.5^{2})

-3.5=-2(x^{2}-x+0.5^{2})

Rewrite as perfect squares

-3.5=-2(x-0.5)^{2}

7/4=(x-0.5)^{2}

square root both sides

x-0.5=(+/-)\sqrt{\frac{7}{4}}

x-\frac{1}{2}=(+/-)\frac{\sqrt{7}}{2}

x=\frac{1}{2}(+/-)\frac{\sqrt{7}}{2}

x=\frac{1+\sqrt{7}}{2}

x=\frac{1-\sqrt{7}}{2}

4 0
3 years ago
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