All categories

3 years ago

What is the solution?

Mathematics

1 answer:

amm18123 years ago

4 0

The answer is no solution because of the lines are extended more they will never touch

You might be interested in

The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

zavuch27 [327]

Answer:

(–1, 1)

(4, –2)

Step-by-step explanation:

Let

(x,y) ----> the coordinates of point C

Applying the Pythagoras Theorem

$(-1-4)^2+(-2-1)^2=(x-4)^2+(y-1)^2+(x+1)^2+(y+2)^2$

step 1

Find the possibles values of x

$(-1-4)^2=(x-4)^2+(x+1)^2\\\\25=x^{2}-8x+16+x^{2}+2x+1\\\\2x^{2}-6x-8=0$

Simplify

$x^{2}-3x-4=0$

Solve the quadratic equation

$x^{2}-3x-4=(x+1)(x-4)$

The values of x are

x=-1 and x=4

step 2

Find the possibles values of y

$(-2-1)^2=((y-1)^2+(y+2)^2\\\\9=y^{2}-2y+1+y^{2}+4y+4\\\\2y^{2}+2y-4=0$

Simplify

$y^{2}+y-2=0$

Solve the quadratic equation

$y^{2}+y-2=(y+2)(y-1)$

The values of y are

y=-2, y=1

therefore

The possibles coordinates of point C are

(-1,1),(4,-2)

3 0

3 years ago

Read 2 more answers

Can someone pleaseeee help if you’re correct I’ll give u brainlist

pickupchik [31]

Answer:

p=65

Step-by-step explanation:

180-50=130

130/2=65

6 0

3 years ago

Read 2 more answers

The distance between Matt's house and his school is 3 inches on the map. The actual distance is 1.5 miles. What is the

MrRissso [65]

The second one 1 inch = 0.5 mile

8 0

4 years ago

Read 2 more answers

Pls help me. I’ll mark BRAINLIEST. Due 10/1/18

KengaRu [80]

Hope this helps you

8 0

3 years ago

If a picnic area is located at the midpoint between Sacramento and Oakland, find the distance to the picnic area from the road s

Oxana [17]

First, think this through. If you are 23 miles from Sacramento, and 110 miles from Oakland (I am assuming it is miles since you didn't specify *cough cough*) then the two cities are 133 miles apart (also assuming you are in between them)
$23miles + 110miles = 133miles$
so, we use the midpoint formula to find our position
$\frac{distance}{ 2}$
and get 66.5 miles from both Sacramento and Oakland.

Next, we already know the sign is 23 miles away from Sacramento so we can use that distance and our position to figure out how far away the sign is. We use absolute values because distance is always positive.
$|our \: position - distance \: of \: sign|$

so we get
$|66.5miles - 23miles| = 43.5miles$
to double check, use the sign's distance from Oakland.
$|66.5miles - 110miles| = 43.5miles$
so, we are 43.5 miles from the sign!

hope this helps

7 0

3 years ago