Sin J: 5/13, 0.38
cos J: 12/13, 0.92
tan J: 5/12, 0.42
sin K: 12/13, 0.92
cos K: 5/13, 0.38
tan K: 12/5, 2.40
Answer:
y = -2/3x - 3
Step-by-step explanation:
y = mx + b
m = slope
(-3,-1) = (x,y)
<em>Plus in the coordinates</em>
-1 = -2/3(-3) + b
<em>negative times negative = positive</em>
-2/3 * -3 = 2
-1 = 2 +b
<em>Use inverse operations</em>
-2 --2
-3 = b
y = -2/3x - 3
To find the z-score for a weight of 196 oz., use

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
Answer:
ok um what’s the question?
Answer:
The answer is 4 1/8
Step-by-step explanation: