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Alex Ar [27]
2 years ago
14

What is the solution?

Mathematics
1 answer:
amm18122 years ago
4 0
The answer is no solution because of the lines are extended more they will never touch
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leva [86]

Answer:

8.j     9.b   10.f    11.a

Step-by-step explanation:

you welcome

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Can someone help me with this please? Thanks! <br><br> Show your work :)
Alexandra [31]
I got 1/81. because u spun the spinner twice i multiplied the regions you are allowed to get by 2 which makes your denominator 18 then you can get the numbers 3 and 6 twice since the spinner is used twice then multiplied them together. so it would be 2/18 x 2/18 = 4/324 which equals 1/81
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3 years ago
This afternoon, Sara noticed that the number of the page assigned for homework is divisible by both 12
max2010maxim [7]

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12

Step-by-step explanation:

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3 years ago
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3 years ago
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Vladimir [108]

Answer:

Exponential decay.

Step-by-step explanation:

You can use a graphing utility to check this pretty quickly, but you can also look at the equation and get the answer. Since the function has a variable in the exponent, it definitely won't be a linear equation. Quadratic equations are ones of the form ax^2 + bx + c, and your function doesn't look like that, so already you've ruled out two answers.

From the start, since we have a variable in the exponent, we can recognize that it's exponential. Figuring out growth or decay is a little more complicated. Having a negative sign out front can flip the graph; having a negative sign in the exponent flips the graph, too. In your case, you have no negatives; just 2(1/2)^x. What you need to note here, and you could use a few test points to check, is that as x gets bigger, (1/2) will get smaller and smaller. Think about it. When x = 0, 2(1/2)^0 simplifies to just 2. When x = 1, 2(1/2)^1 simplifies to 1. Already, we can tell that this graph is declining, but if you want to make sure, try a really big value for x, like 100. 2(1/2)^100 is a value very very very veeery close to 0. Therefore, you can tell that as the exponent gets larger, the value of the function goes down and gets closer and closer to zero. This means that it can't be exponential growth. In the case of exponential growth, as the exponent gets bigger, your output should increase, too.

3 0
3 years ago
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