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Novay_Z [31]
3 years ago
14

Determine the next step for solving the quadratic equation by completing the square.

Mathematics
1 answer:
Studentka2010 [4]3 years ago
4 0

Answer:

The solutions are x=\frac{1+\sqrt{7}}{2} and x=\frac{1-\sqrt{7}}{2}

Step-by-step explanation:

we have

0=-2x^{2}+2x+3

Group terms that contain the same variable, and move the constant to the opposite side of the equation

-3=-2x^{2}+2x

Factor the leading coefficient

-3=-2(x^{2}-x)

Complete the square. Remember to balance the equation by adding the same constants to each side.

-3-0.5=-2(x^{2}-x+0.5^{2})

-3.5=-2(x^{2}-x+0.5^{2})

Rewrite as perfect squares

-3.5=-2(x-0.5)^{2}

7/4=(x-0.5)^{2}

square root both sides

x-0.5=(+/-)\sqrt{\frac{7}{4}}

x-\frac{1}{2}=(+/-)\frac{\sqrt{7}}{2}

x=\frac{1}{2}(+/-)\frac{\sqrt{7}}{2}

x=\frac{1+\sqrt{7}}{2}

x=\frac{1-\sqrt{7}}{2}

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The answer is b just took it
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3 years ago
Which sequence is generated by the function f(n + 1) = f(n) – 2 for f(1) = 10?
PSYCHO15rus [73]

Answer: The sequence generated is 10, 8, 6, 4, 2, ...

This sequence is arithmetic with starting term 10 and common difference -2. This means we add -2 to each term to get the next one (same as subtracting 2 from each term). This common difference is directly connected to the -2 from the recursive rule f(n+1) = f(n)-2

Whatever the nth term f(n) is, we subtract off 2 to get f(n)-2 to get the f(n+1) term, which is right after the nth term.

3 0
4 years ago
Read 2 more answers
The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?
svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

V(t) = V(0)(1-r)^{t}

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that r = 0.16

So

V(t) = V(0)(1-r)^{t}

V(t) = V(0)(1-0.16)^{t}

V(t) = V(0)(0.84)^{t}

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

V(t) = V(0)(0.84)^{t}

0.5V(0) = V(0)(0.84)^{t}

(0.84)^{t} = 0.5

\log{(0.84)^{t}} = \log{0.5}

t\log{0.84} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.84}}

t = 3.98

The half life of the car is 3.98 years.

7 0
4 years ago
Chloe and denise bought a identical t-shirts from the same shop.Chloe bought on monday when there was a 15% off the original pri
RoseWind [281]
The original price was 7.

Chloe got a 15% discount; this means she paid 100-15 = 85% of the price.  Letting x be the price, Chloe paid 0.85x.

Denise got a 20% discount; this means she paid 100-20 = 80% of the price.  Denise paid 0.8x.

We know that Chloe paid 35p more; this gives us the equation
0.85x = 0.8x + 0.35

We do not want a variable on both sides, so we subtract 0.8x from both:
0.85x - 0.8x = 0.8x + 0.35 - 0.8x
0.05x = 0.35

Divide both sides by 0.05:
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7 0
4 years ago
Please help with this one question
AURORKA [14]

Answer:

C

Step-by-step explanation:

Good luck, I'm so so so sorry if i am wrong

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