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Novay_Z [31]
3 years ago
14

Determine the next step for solving the quadratic equation by completing the square.

Mathematics
1 answer:
Studentka2010 [4]3 years ago
4 0

Answer:

The solutions are x=\frac{1+\sqrt{7}}{2} and x=\frac{1-\sqrt{7}}{2}

Step-by-step explanation:

we have

0=-2x^{2}+2x+3

Group terms that contain the same variable, and move the constant to the opposite side of the equation

-3=-2x^{2}+2x

Factor the leading coefficient

-3=-2(x^{2}-x)

Complete the square. Remember to balance the equation by adding the same constants to each side.

-3-0.5=-2(x^{2}-x+0.5^{2})

-3.5=-2(x^{2}-x+0.5^{2})

Rewrite as perfect squares

-3.5=-2(x-0.5)^{2}

7/4=(x-0.5)^{2}

square root both sides

x-0.5=(+/-)\sqrt{\frac{7}{4}}

x-\frac{1}{2}=(+/-)\frac{\sqrt{7}}{2}

x=\frac{1}{2}(+/-)\frac{\sqrt{7}}{2}

x=\frac{1+\sqrt{7}}{2}

x=\frac{1-\sqrt{7}}{2}

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Five workers are hired to seed a field by hand. Each is given a plot which is 6x12 feet in size. What is the total area of the f
Lorico [155]

Answer:

360 feet

Step-by-step explanation:

multiple 6 by 12 to get the area of the individual plot of land given to a single worker.

Then multiply by 5 for all 5 workers getting the same plot of land.

3 0
3 years ago
What is the Sum of 5 times z and 4 divided by two is 7
8_murik_8 [283]
Sum of 5 times z and 4 divided by two is 7.

\frac{5z+4}{2} = 7
3 0
3 years ago
Read 2 more answers
a team of 10 players is to be selected from a class of 6 girls and 7 boys. match each scenario to its probability
mars1129 [50]

Step-by-step explanation:

The selection of r objects out of n is done in

many ways.

The total number of selections 10 that we can make from 6+7=13 students is  

thus, the sample space of the experiment is 286

A.  

"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.

P(all 6 girls chosen)=35/286=0.12

B.

"The probability that a randomly chosen team has 3 girls and 7 boys."

with the same logic as in A, the number of groups were all 7 boys are in, is  

so the probability is 20/286=0.07

C.

"The probability that a randomly chosen team has either 4 or 6 boys."

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is 0.12.

case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls.  

the probability is 105/286=0.367

since  case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.

"The probability that a randomly chosen team has 5 girls and 5 boys."

selecting 5 boys and 5 girls can be done in  

many ways,

so the probability is 126/286=0.44

Did this help??

8 0
3 years ago
52 – 4 &gt; – 29 AND – 12 + 6 &gt; 2<br> Solve and give answer in interval notation
BlackZzzverrR [31]

Answer:

wait huh?im confused lol

Step-by-step explanation:

6 0
3 years ago
J
UNO [17]
T - Shirts = $10
SweatShirts = 15$

24 *15 =360$

105 - 24 = 81

81 * 10 = 810$

810 + 360 = 1170$

T shirts = 81
Sweat= 24. /A\is the correct Answer
8 0
3 years ago
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