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marta [7]
2 years ago
13

The expression 1000(1.1)^t represents the value of a $1000 investment that earns 10% interest per year, compunded annually for t

years. What is the value of a $1000 investment at the end of each period? 1) 2 years 2) 4 years
Mathematics
1 answer:
Dmitriy789 [7]2 years ago
6 0
The answer is : 2 ~Year: A=1000(1.1)^2 A=$1210 For 4 Year: A=1000(1.1)^4 A=$1464.10
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Answer:

X is negative 5/ -5

Step-by-step explanation:

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Match the key features of functions terms to their corresponding definitions.
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<h3>Definition of terms</h3>

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Is This Substitution?

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3 years ago
Given the functions: f(x) = x^2-9 and g(x) = 3 what is (f/g)(x)? A. x-3 B. x-9 C. x+3 D. x+9
uysha [10]

Answer:

f + g)(x) = f (x) + g(x)

= [3x + 2] + [4 – 5x]

= 3x + 2 + 4 – 5x

= 3x – 5x + 2 + 4

= –2x + 6

(f – g)(x) = f (x) – g(x)

= [3x + 2] – [4 – 5x]

= 3x + 2 – 4 + 5x

= 3x + 5x + 2 – 4

= 8x – 2

(f × g)(x) = [f (x)][g(x)]

= (3x + 2)(4 – 5x)

= 12x + 8 – 15x2 – 10x

= –15x2 + 2x + 8

\left(\small{\dfrac{f}{g}}\right)(x) = \small{\dfrac{f(x)}{g(x)}}(

g

f

)(x)=

g(x)

f(x)

= \small{\dfrac{3x+2}{4-5x}}=

4−5x

3x+2

My answer is the neat listing of each of my results, clearly labelled as to which is which.

( f + g ) (x) = –2x + 6

( f – g ) (x) = 8x – 2

( f × g ) (x) = –15x2 + 2x + 8

\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}

3 0
2 years ago
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