Answer:
No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.
For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
2
in.
+
3
in.
=
5
in.
5
in.
<
6
in.
For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:
3 + 4 = 7 which is greater than 5
3 + 5 = 8 which is greater than 4
4 + 5 = 9 which is greater than 3
Step-by-step explanation:
Lets start with the chain of 3's:
18 = 3 + 3 + 3 + 3 + 3 + 3
But, we know that
3 + 3 = 2 + 2 + 2
Sol, let's replace 3 + 3 by 2 + 2 + 2 one by one.
Hence, the possible ways of combinations are listed below:
18 = 3 + 3 + 3 + 3 + 2 + 2 + 2 (1)
18 = 3 + 3 + 2 + 2 + 2 + 2 + 2 + 2 (2)
Therefore, there are two combinations of 2- and 3- point shots that could total 18 points.
Answer:
(x) = 
Step-by-step explanation:
let y = f(x) and rearrange making x the subject, that is
y = 5x + 4 ( subtract 4 from both sides )
y - 4 = 5x ( divide both sides by 5 )
= x
change x to (x) and y back to x, thus
(x) =
Answer:
2/4
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
