275??
16×=4400
16×/16=4400/16
x=275
the value of Y is when X crosses the X axis.
Answer:
Step-by-step explanation:
Answer:
the answer is C.
Step-by-step explanation:
the sum of the problem is 8.164.... so 8/C is the answer
Answer:
(a) 91 employees were absent fewer than six days.
(b) 22 employees were absent more than five days.
(c) 20 employees were absent from 6 up to 12 days.
Step-by-step explanation:
The data for the number of days absent during a calendar year by employees of a manufacturing company is given below.
(a)
The number of employees that were absent for fewer than six days is =
![Frequency\ for\ class\ [0\ - \ 3]+Frequency\ for\ class\ [3\ - \ 6]\\=60 +31\\=91](https://tex.z-dn.net/?f=Frequency%5C%20%20for%5C%20%20class%5C%20%5B0%5C%20-%20%5C%203%5D%2BFrequency%5C%20%20for%5C%20%20class%5C%20%5B3%5C%20-%20%5C%206%5D%5C%5C%3D60%20%2B31%5C%5C%3D91)
Thus, there were 91 employees who were absent for fewer than six days.
(b)
The number of employees that were absent for more than 5 days is =
![Frequency\ for\ class\ [6\ -\ 9]+Frequency\ for\ class\ [9\ -\12]+\\Frequency\ for\ class\ [12\ - \15]\\=14+6+2\\=22](https://tex.z-dn.net/?f=Frequency%5C%20%20for%5C%20%20class%5C%20%5B6%5C%20-%5C%209%5D%2BFrequency%5C%20%20for%5C%20%20class%5C%20%5B9%5C%20-%5C12%5D%2B%5C%5CFrequency%5C%20for%5C%20%20class%5C%20%5B12%5C%20-%20%5C15%5D%5C%5C%3D14%2B6%2B2%5C%5C%3D22)
Thus, there were 22 employees who were absent for more than 5 days.
(c)
The number of employees that were absent from 6 up to 12 days is =
![Frequency\ for\ class\ [6\ -\ 9]+Frequency\ for\ class\ [9\ -\12]=14+6\\=20](https://tex.z-dn.net/?f=Frequency%5C%20%20for%5C%20%20class%5C%20%5B6%5C%20-%5C%209%5D%2BFrequency%5C%20%20for%5C%20%20class%5C%20%5B9%5C%20-%5C12%5D%3D14%2B6%5C%5C%3D20)
Thus, there were 20 employees who were absent from 6 up to 12 days.