Find the quotient of x^3 + 4x^2 - x

How do I solve this ?

Monica [59]

Change the 5 - 2t with kcc (keep,change,change)and make it 5+-2t=3t

5 0

3 years ago

Factores de 12 028 pr favor estoy en apuros

const2013 [10]

Answer:

hbfbdsfbdhjdfjhbfbggybfb

Step-by-step explanation:

shjbuydbyubfrbgbybfybg

5 0

3 years ago

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e

professor190 [17]

Answer:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

$n=15$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =16$ represent the sample variance

$\sigma^2_0 =25$ represent the value that we want to verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 25$

Alternative hypothesis: $\sigma^2$

The statistic is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And replacing we got:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

6 0

3 years ago

Which of the following are equations for the line shown below? Check all that apply.

Nuetrik [128]

Answer: D. $y+4=(x+2)$

Step-by-step explanation: Once you subtract $4$ from both sides, in order to solve for y (as the equation needs to be in the slope-intercept form, otherwise known as $y=mx+b$ ), you end up with $y=x-2$ , which is the right answer. It is the correct answer because the y-intecept shown in the equation matches what is on the graph, in addition to the fact that the slope is just $x$ .