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DIA [1.3K]
3 years ago
6

100 points, will mark BRAINLIEST. Please help with the attached question, thank you. I'd appreciate if you didn't mark anything

as an answer. Thank you, :)

Mathematics
2 answers:
Ksivusya [100]3 years ago
6 0

Answer:

The answer to your question is:  2nd option is correct.

Step-by-step explanation:

Data

slope = m = -4

Point = (-3, 1)

Formula

             (y - y1) = m(x - x1)

            y - 1 = -4(x - (-3))                 Substitution

e-lub [12.9K]3 years ago
4 0

Answer:

y - 1 = -4[x-(-3)]

Step-by-step explanation:

m = -4

y = -4x + b

1 = 12 + b

-11 = b

y = -4x - 11

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In algebra, we use a(n) to represesent a veriable
nekit [7.7K]

Answer:

Are you Algebra 1 or 2?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
determine the point of intersection of the following pair of lines ............2x-3y-4=-13 and 5x=-2y+25. 3x+2y-7=0 and 2x=12-5y
grandymaker [24]

Answer:

  1. (x, y) = (3, 5)
  2. (x, y) = (1, 2)

Step-by-step explanation:

A nice graphing calculator app makes these trivially simple. (See the first two attachments.) It is available for phones, tablets, and as a web page.

__

The usual methods of solving a system of equations involve <em>elimination</em> or <em>substitution</em>.

There is another method that is relatively easy to use. It is a variation of "Cramer's Rule" and is fully equivalent to <em>elimination</em>. It makes use of a formula applied to the equation coefficients. The pattern of coefficients in the formula, and the formula itself are shown in the third attachment. I like this when the coefficient numbers are "too messy" for elimination or substitution to be used easily. It makes use of the equations in standard form.

_____

1. In standard form, your equations are ...

  • 2x -3y = -9
  • 5x +2y = 25

Then the solution is ...

  x=\dfrac{-3(25)-(2)(-9)}{-3(5)-(2)(2)}=\dfrac{-57}{-19}=3\\\\y=\dfrac{-9(5)-(25)(2)}{-19}=\dfrac{-95}{-19}=5\\\\(x,y)=(3,5)

__

2. In standard form, your equations are ...

  • 3x +2y = 7
  • 2x +5y = 12

Then the solution is ...

  x=\dfrac{2(12)-5(7)}{2(2)-5(3)}=\dfrac{-11}{-11}=1\\\\y=\dfrac{7(2)-12(3)}{-11}=\dfrac{-22}{-11}=2\\\\(x,y)=(1,2)

_____

<em>Note on Cramer's Rule</em>

The equation you will see for Cramer's Rule applied to a system of 2 equations in 2 unknowns will have the terms in numerator and denominator swapped: ec-bf, for example, instead of bf-ec. This effectively multiplies both numerator and denominator by -1, so has no effect on the result.

The reason for writing the formula in the fashion shown here is that it makes the pattern of multiplications and subtractions easier to remember. Often, you can do the math in your head. This is the method taught by "Vedic maths" and/or "Singapore math." Those teaching methods tend to place more emphasis on mental arithmetic than we do in the US.

7 0
4 years ago
5.2x+8+2.1x-3 which is an equivalent expression by combining like terms A. 5.2x+8+2.1x-3 B. 5.2x+5+2.1x C 13.2x-0.9x D 7.3x+5
satela [25.4K]

Answer: 7.3x + 5

Step-by-step explanation:

For us to solve the question, we have to solve 5.2x+8+2.1x-3 and the answer gotten will allow us know the equivalent expression.

= 5.2x+8+2.1x-3

= 5.2x + 2.1x + 8 - 3

= 7.3x + 5

Therefore, the correct answer is 7.3x + 5

7 0
3 years ago
What is the slope of the line that contains the point (13,-2) and (3,-2)
ra1l [238]

The slope of the line that contains the point (13,-2) and (3,-2) is 0

<em><u>Solution:</u></em>

Given that we have to find the slope of the line

The line contains the point (13,-2) and (3,-2)

<em><u>The slope of line is given as:</u></em>

m = \frac{y_2-y_1}{x_2-x_1}

Where, "m" is the slope of line

Here given points are (13,-2) and (3,-2)

(x_1, y_1) = (13, -2)\\\\(x_2, y_2) = (3, -2)

<em><u>Substituting the values in formula, we get,</u></em>

m = \frac{-2-(-2)}{3-13}\\\\m = \frac{-2+2}{3-13}\\\\m = 0

Thus the slope of line is 0

3 0
3 years ago
What is the 60th term of the sequence 2, -3, -8, -13?
aleksandrvk [35]

Answer:

  -293

Step-by-step explanation:

The first term of the arithmetic sequence is a1 = 2. The common difference is d = -3-2 = -5. The general term is ...

  an = a1 +d(n -1)

  an = 2 -5(n -1)

The 60th term is ...

  a60 = 2 -5(60 -1) = -293

4 0
3 years ago
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