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3 years ago

HEB has dish soap that costs $2.80 for a 12oz bottle. Fiesta has the same dish soap that costs $2.00 for a 8 oz tube.

Mathematics

1 answer:

s2008m [1.1K]3 years ago

4 0

Answer:

The unit rate at HEB is $0.23 per ounce. The unit rate at Fiesta is $0.25 per ounce. So HEB has the better buy for dish soap.

Step-by-step explanation:

To calculate unit rate, you divide the price by the oz.

So for HEB, you should do $2.80/12 oz. This will equal to $0.23 per ounce. For Fiesta, you should do $2.00/8 oz. This will equal to $0.25 per ounce.

To determine which one is the better buy, the lower priced one is better, meaning HEB is the better buy.

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The newly elected president needs to decide the remaining 5 spots available in the cabinet he/she is appointing. If there are 15

skad [1K]

Answer: There are 360360 ways to appoint the members of the cabinet.

Step-by-step explanation:

Since we have given that

Number of eligible candidates = 15

Number of spots available = 5

We need to find the number of different ways the members can be appointed where rank matters

For this we will use "Permutations":

So, the required number of different ways in choosing the members for appointment is given by

$^{15}P_5=360360$

Hence, there are 360360 ways to appoint the members of the cabinet.

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3 years ago

What type of triangle is shown in the image?

frutty [35]

The triangle is an Obtuse triangle

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Multiply or divide. Show your work.<br><br> 3n²-n/n²-1÷n²/n+1

Ugo [173]

$\frac{3n^{2} - n}{n^{2} - 1} \div \frac{n^{2}}{n + 1}$
$\frac{n(3n) - n(1)}{n^{2} + n - n - 1} \div \frac{n^{2}}{n + 1}$
$\frac{n(3n - 1)}{n(n) + n(1) - 1(n) - 1(1)} \div \frac{n^{2}}{n + 1}$
$\frac{n(3n - 1)}{n(n + 1) - 1(n + 1)} \div \frac{n^{2}}{n + 1}$
$\frac{n(3n - 1)}{(n - 1)(n + 1)} \div \frac{n^{2}}{n + 1}$
$\frac{n(3n - 1)}{(n - 1)(n + 1)} * \frac{n + 1}{n^{2}}$
$\frac{3n - 1}{n - 1} * \frac{1}{n}$
$\frac{3n - 1}{n(n - 1)}$

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3 years ago

Which statement is true for the equation 4n – 3 = 4n – 2 Select one: a. It has no solution. b. It has one solution. c. It has tw

oksian1 [2.3K]

4n-3=4n-2 subtract 4n from both sides

-3=-2

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So your answer is a.

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3 years ago

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Vic is standing on the ground at a point directly south of the base of the CN Tower and can see the top when looking at an angle

Sindrei [870]

The angle of elevation of 61° and 72° with the height of the tower being 553.3 m. gives Vic's distance from Dan as approximately 356 meters.

<h3>How can the distance between Vic and Dan be calculated?</h3>

Location of Vic relative to the tower = South

Vic's sight angle of elevation to the top of the tower = 61°

Dan's location with respect to the tower = West

Dan's angle of elevation in order to see the top of the tower = 72°

Height of the tower = 553.3m

$tan( \theta) = \frac{opposite}{adjacent}$

$tan( 61 ^{ \circ}) = \frac{553.3}{ Vic' s\: distance \: to \: tower}$

$distance = \frac{553.3}{tan ( {61}^{ \circ} )} = 306.7$

Vic's distance from the tower ≈ 306.7 m

Similarly, we have;

$Dan's distance = \frac{553.3}{tan ( {72}^{ \circ} )} = 179.8$

Dan's distance from the tower ≈ 179.8 m

Given that Vic and Dan are at right angles relative to the tower (Vic is on the south of the tower while Dan is at the west), by Pythagorean theorem, the distance between Vic and Dan <em>d </em>is found as follows;

d = √(306.7² + 179.8²) ≈ 356

Therefore;

Vic is approximately 356 meters from Dan

Learn more about Pythagorean theorem here:

brainly.com/question/343682

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