Answer:
#include <iostream>
using namespace std;
int main()
{
int exam1 = 70;
int exam2 = 85;
int examAverage;
examAverage = (exam1+exam2)/2;
cout <<"The Average of Exam1 and Exam2 is: "<<examAverage<<endl;
return 0;
}
Explanation:
Using the C++, we declare the three variables all of type
exam1
exam2 and
examAverage
We assign initial values of 70 and 85 to exam1 and exam2 respectively
Is simple likeness. Historically, in fact, artists used self-portraits as a kind of calling card, attesting to their ability to capture a likeness and giving a sense of their capabilities. And, yes, self-portraits are convenient exercises because the model is always available and works for free
Answer:
C. sqrt(Math)
Explanation:
All but one of options A to E are is not a static method.
Only option C is a static method. The sqrt() is a static method of Math, that can always be used as Math.sqrt() is used;
The Math class defines all of its methods to be static. Invoking Math methods is done by using Math as a method rather than a variable of type Math; this means that sqrt(Math) doesn't rely on instance variables and don't need to be overridden, unlike others.
Lastly, sqrt(Math) is a static method because unlike other options, it is an utility method, and it is relevant to computations on primitive data types.
The purpose of the static method is in large part to offer a standard library of functions, and it doesn't need to be applied directly to an object.
Your answer your looking for is letting D because you don’t know it or it don’t have anything to do with you...
