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Paha777 [63]
3 years ago
7

7

Computers and Technology
1 answer:
Alex17521 [72]3 years ago
4 0

Answer:

Number of CDs = 7

Explanation:

We know that

1 GB = 1024 MB

So it means the 4 GB of data can be interpreted as:

4 GB = 1024*4 MB

4GB = 4096 MB

So a DVD hold 4096 MB of data while a CD holds 650 MB of data.

We need to find how many CDs could hold 4096 MB of data, to make it equivalent to a DVD

Number of CDs = 4096/650

Number of CDs= 6.3

As a CD can not be 0.3, a whole 1 CD will be used.

Number of CDs = 7

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Modify the program you wrote for Chapter 6 Exercise 6 so it handles the following
Basile [38]

Answer:

#try except

try:

   #opening the file

   read_file = open('numbers.txt', 'r')

   #Store the numbers in the variable file_numbers.

   file_numbers = read_file.read()

   #close the file

   read_file.close()

   #Split the number of files in list_values.

   list_values = file_numbers.split()

   #how many numbers are there

   list_length = len(list_values)

   try:

       #loop it up

       for i in range(list_length):

           list_values[i] = float(list_values[i])

       #Add up all the numbers, put into list_sum

       List_sum = sum(list_values)

       #heres how we average it

       Average_value = (List_sum)/list_length

       #print

       print(Average_value)

   except ValueError:

       print( "File must have only numbers. Try again." )

   #handles IOError exceptions

except IOError:

   #Display statement

   print("Trouble opening file. Try again.")

Explanation:

The python program uses the try-except exception handling method to catch errors in the code. The IOError is used for catching input and output errors in the program like file handling while the ValueError keyword in the except statement is used to catch data type errors from a return statement, calculation or user input.

6 0
3 years ago
Use python
Degger [83]

Answer:

def rec_dig_sum( num ):

   num_list = [ digit for digit in str(num)]

   total = 0

   for x in num_list:

       total += x

   return total

def dict_of_rec_dig_sums(low, high):

   mydict = dict()

   for number in the range(low, high+1):

      mydict[rec_dig_sum(number)] = number

   return mydict

Explanation:

The python program defines two functions, "rec_dig_sum" and "dict_of_rec_dig_sums". The former accepts a number and returns the sum of the digits of the number while the latter accepts a low and high number range.

The program returns a dictionary with the recursive sum as the keys and the number count as the values.

3 0
3 years ago
Analyze the code and identity the value of variable a,b and c after the code execution. int a=40, b=50, c=60; if(! (a>=40)) b
AlekseyPX

Answer:

a=40,b=30,c=60

The answer is B

7 0
3 years ago
To save a file so that it can be opened on most computers, select the _____ option.
romanna [79]
Save it on the cloud.
6 0
4 years ago
Read 2 more answers
Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have alre
Fudgin [204]

Answer:

The c++ program to implement the while loop is given below.

#include <iostream>

using namespace std;

int main() {

  // declaration of integer variables

   int k, n, total;

   // initialization of integer variables

   k=1, n=4, total=0;

//  loop executed till value of k becomes equal to value of n

   while( k <= n ){

       // cube of every integer is added to the variable total

       total = total + ( k * k * k );

       // value of k is incremented to go to the next number

k = k + 1 ;

   }  

   return 0;

}  

Explanation:

The program begins with the declaration of integer variables.  

int k, n, total;

This is followed by initialization of these variables.

k=1, n=4, total=0;

The while loop runs over the variable k which is initialized to 1. The loop runs till value of k reaches the value of integer n.

First, cube of k is computed and added to the variable total.

After first execution of the loop, total is initialized to the cube of 1.

Next, value of variable k is incremented by 1 so that k is initialized to next integer.

After first execution of the loop, k is incremented from 1 to 2.

while( k <= n )

{

total = total + ( k * k * k );

k = k + 1 ;

   }

When the value of k reaches the value of integer n, the cube of n is calculated and added to the variable, total.

When k is incremented, it becomes more than n and hence, loop gets terminated.

As the return type of main is int, the program terminates with the statement shown below.

return 0;

No output is displayed as it is not mentioned in the question.

No user input is taken as it is mentioned that integer variables are already initialized.

4 0
3 years ago
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