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2 years ago

Please help with 1 , and 2 I really don’t understand this!

Mathematics

2 answers:

makvit [3.9K]2 years ago

8 0

Answer:

1.B

2.A

<em>Hope it helped all of you....</em>

elena-s [515]2 years ago

6 0

1. B
2. A

hope this helped

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Help plz idk I need help ASAP

rjkz [21]

Answer:

1. A

2. - (b)

3. a = c - b

8 0

2 years ago

√4/9 =? <br><br>I need help finding the missing number.

kotykmax [81]

√4 / 9

√4 = 2

So the answer would be....

2 / 9

Hope this helps!

7 0

3 years ago

Read 2 more answers

What is the answer to this question?

timurjin [86]

Answer: Option 1

Step-by-step explanation:

See attached image

3 0

1 year ago

A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch

ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

Then,

$P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\$

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0

2 years ago

Select the graph of y=cot x.

Kisachek [45]

Because of the vertical asymptote and the change in concavity, we conclude that the correct option is B.

<h3>Which is the graph of cotangent of x?</h3>

Remember that cot(x) = 1/tan(x).

Then we can rewrite:

cot(x) = cos(x)/sin(x).

We know that for x = 0, we have:

cot(0) = cos(0)/sin(0) = 1/0

Then we have a vertical asymptote that tends to ± infinity.

The only graph that meets this condition is the second and the third one, and by the curvature (we need to have a change of concavity/convexity) in the tangent function.

From that, we conclude that the correct option is B.

If you want to learn more about trigonometric functions:

brainly.com/question/8120556

#SPJ1

7 0

1 year ago