Ask question

Ask question

All categories

BabaBlast [244]

3 years ago

5

find the distance between P1 (3,-195degrees) and P2 (-4, -94 degrees) on the polar plane. Round your answer to the nearest thous

andth.

1 answer:

Ronch [10]3 years ago

8 0

This is distance formula is sqr. root of (x1-x2)^2 + (y1-y2)^2
(3-(-4))^2+ (-94-(-195))
7^2 101^2
49+ 10,201
square root of 10250
101.242 or the closest answer to this

You might be interested in

(c = -3)<br><br> 5c + 4c + c = ?

Allisa [31]

Hey there!

5c + 4c + c

= 5(-3) + 4(-3) - 3

= -15 - 12 - 3

= -27 - 3

= -30

Therefore, your answer is: -30

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

8 0

2 years ago

It too Mrs. phillips 1.6 hours to run the 13.2 miles. What was his average speed

MariettaO [177]

Answer:

13.2 miles/ 1.6 hours= 8.25 miles/hour.Mr. Phillips's speed was 8.25

7 0

3 years ago

Solve by factoring...<br><br> 1) y=6x^2-13x-5<br><br> 2) y=4x^2-7x+3

Amanda [17]

Answer:

1) $x=-\frac{1}{3}, x=\frac{5}{2}$

2) $x=1, x=\frac{3}{4}$

Step-by-step explanation:

1)

Given

$f(y)= 6x^{2} -13x-5=0$

Equating above equation.

$6x^{2} +2x-15-5=0$

$2x(3x+1)-5(3x+1)=0$

$(3x+1)(2x-5)=0$

Solving for both the equation

$3x+1=0$

$3x=-1$

$x=-\frac{1}{3}$

$2x-5=0$

$2x=5$

$x=\frac{5}{2}$

$x=-\frac{1}{3} ,x=\frac{5}{2}$

2)

Given

$f(y)=4x^{2} -7x+3=0$

$4x^{2} -4x-3x+3=0$

$4x(x-1)-3(x-1)=0$

$(x-1)(4x-3)=0$

Solving for both equation

$x-1=0$

$x=1$

$4x-3=0$

$4x=3$

$x=\frac{3}{4}$

$x=1, x=\frac{3}{4}$

8 0

4 years ago

Simplify 25^ - 1/2 <br><br>Please explain! I know the answer is 1/5 but why?

lisov135 [29]

$(25)^{-\frac{1}{2} }$

When the exponent is negative, you have to make the number a fraction(1 over the number).

For example:

$25^{-2} = \frac{1}{25^{2} }$

$x^{-1} =\frac{1}{x^{1} }$

This gets rid of the negative, but it leaves the exponent

$(25)^{-\frac{1}{2}} = \frac{1}{25^{1/2}}$

When an exponent is a fraction, it is the square root.

For example:

$x^{\frac{1}{3}} = \sqrt[3]{x}$

$x^{\frac{1}{2}} =\sqrt{x}$

$x^{\frac{1}{4}}=\sqrt[4]{x}$

So...

$\frac{1}{25^{1/2}} = \frac{1}{\sqrt{25} } = \frac{1}{5}$

3 0

3 years ago

Rectangle divided into four rectangles. The perimeters of rectangle #1, #2, #3, #4 are 10 cm, 20 cm, 28 cm and 18 cm respectivel

notsponge [240]

Answer:

Perimeter of big rectangle = 38 units

Step-by-step explanation:

Let the sides of rectangle (1) = a and c cm

Sides of rectangle (2) = b and c cm

Sides of rectangle (3) = b and d cm

Sides of rectangle (4) = a and d cm

Perimeter of (1) = 2(length + width)

2(a + c) = 10

a + c = 5 ---------(1)

Perimeter of (2) = 2(b + c)

2(b + c) = 20

b + c = 10 -------(2)

Perimeter of (3) =2(b + d)

2(b + d) = 28

b + d = 14 --------(3)

Perimeter of (4) = 2(a + d)

2(a + d) = 18

a + d = 9 -------(4)

Since perimeter of the big rectangle = 2(a + b + c + d)

By adding equations (1) + (2) + (3) + (4),

(a + c) + (b + c) + (b + d) + (a + d) = 5 + 10 + 14 + 9

2(a + b + c + d) = 38

Therefore, perimeter of the rectangle ABCD = 38 units

7 0

3 years ago