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dalvyx [7]
3 years ago
9

The sum of two integers is 64. The larger is 16 more than three times the smaller. Find the two integers.

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
3 0

Answer:

12 and 52

Step-by-step explanation:

Let x and y be the 2 integers with x > y, then

x + y = 64 and

x = 3y + 16 ( 16 more than 3 times the smaller )

Substitute x = 3y + 16 into x + y = 64, that is

3y + 16 + y = 64

4y + 16 = 64 ( subtract 16 from both sides )

4y = 48 ( divide both sides by 4 )

y = 12 and x = 3(12) + 16 = 36 + 16 = 52

The 2 integers are 12 and 52

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During a sale a dress marked down from a selling price of $80 to a sale price of $64. What is the percent markdown
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3 years ago
Point R is on line segment QS. Given RS=11 and QS=19, determine the length QR.
never [62]
<h3>Answer: QR is 8 units long</h3>

================================================

Explanation:

R is between Q and S and on segment QS, allowing us to say

QR + RS = QS

because of the segment addition postulate.

-------

Use substitution and solve for QR

QR + RS = QS

QR + 11 = 19

QR = 19 - 11 .... subtracting 11 from both sides

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4 0
3 years ago
Please help on how to get last few marks
Strike441 [17]

Answer:

K = 12

Step-by-step explanation:

10 Cos 30° – 3 Tan 60°

The above expression can be simplified as follow:

10 Cos 30° – 3 Tan 60°

Recall:

Cos 30° = √3/2

Tan 60° = √3

Therefore,

10 Cos 30° – 3 Tan 60°

10 (√3/2) – 3(√3)

5√3 – 3√3

(5 – 3) √3

2√3

To write the above expression 2√3 in the form √K, we simply do the following:

2√3

Find a number, such that the square root of the number will result to 2. The number is 4 as shown below

√4 = 2

Next, replace 2 with √4 in the expression above

2√3

= √4 × √3

= √(4 × 3)

= √12

Therefore,

2√3 = √12

Comparing √12 with √K,

√12 = √K

K = 12

3 0
3 years ago
James is fencing off a triangular region for his cats to play in. From the first fence post, he walks 13 meters in a straight li
solniwko [45]
The answer is B. 16.1 square meters

The region has triangular shape. To calculate the area of the triangle when three sides are known, we will use the Heron's formula:
A = √s(s-a)(s-b)(s-c)
where:
A - the area of the triangle
a, b, and c - the sides of the triangle
s - half of the triangle's perimeter: s = (a+b+c)/2

It is given:
a = 13 m
b = 5 m
c = 9 m

First, calculate s:
s = (a+b+c)/2 = (13+5+9)/2 = 13.5

Now, it is easy to calculate the area:
A = <span>√s(s-a)(s-b)(s-c) = </span>√13.5(13.5-13)(13.5-5)(13.5-9) = √13.5×0.5×8.5×4.5 = √258.19 = 16.07 ≈ 16.1
3 0
3 years ago
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