<h3>
Answer: QR is 8 units long</h3>
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Explanation:
R is between Q and S and on segment QS, allowing us to say
QR + RS = QS
because of the segment addition postulate.
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Use substitution and solve for QR
QR + RS = QS
QR + 11 = 19
QR = 19 - 11 .... subtracting 11 from both sides
QR = 8
Answer:
K = 12
Step-by-step explanation:
10 Cos 30° – 3 Tan 60°
The above expression can be simplified as follow:
10 Cos 30° – 3 Tan 60°
Recall:
Cos 30° = √3/2
Tan 60° = √3
Therefore,
10 Cos 30° – 3 Tan 60°
10 (√3/2) – 3(√3)
5√3 – 3√3
(5 – 3) √3
2√3
To write the above expression 2√3 in the form √K, we simply do the following:
2√3
Find a number, such that the square root of the number will result to 2. The number is 4 as shown below
√4 = 2
Next, replace 2 with √4 in the expression above
2√3
= √4 × √3
= √(4 × 3)
= √12
Therefore,
2√3 = √12
Comparing √12 with √K,
√12 = √K
K = 12
The answer is B. 16.1 square meters
The region has triangular shape. To calculate the area of the triangle when three sides are known, we will use the Heron's formula:
A = √s(s-a)(s-b)(s-c)
where:
A - the area of the triangle
a, b, and c - the sides of the triangle
s - half of the triangle's perimeter: s = (a+b+c)/2
It is given:
a = 13 m
b = 5 m
c = 9 m
First, calculate s:
s = (a+b+c)/2 = (13+5+9)/2 = 13.5
Now, it is easy to calculate the area:
A = <span>√s(s-a)(s-b)(s-c) = </span>√13.5(13.5-13)(13.5-5)(13.5-9) = √13.5×0.5×8.5×4.5 = √258.19 = 16.07 ≈ 16.1
