Ask question

Ask question

All categories

sergij07 [2.7K]

4 years ago

13

Please Help?!

2 answers:

alina1380 [7]4 years ago

7 0

<span>The equations that show a direct variation between x and y when solved for y are:

</span><span>A. -10+y=3x-10
B. y=-1/8x
</span>
Since k is constant (the same for every point), we can find k when given any point by dividing the y<span>-coordinate by the </span>x<span>-coordinate. For example, if </span>y varies<span> directly as </span>x , and y<span> = 6 when </span>x<span> = 2 , the constant of </span>variation<span> is k = = 3 . Thus, the equation describing this </span>direct variation<span> is </span>y<span> = 3x .</span>

Yuliya22 [10]4 years ago

6 0

Hello there.

<span>Please Help?!
Which equations show a direct variation between x and y when solved for y?

Choose ALL answers that are correct.

</span><span>A. -10+y=3x-10
B. y=-1/8x</span>

You might be interested in

Estimate 29.14 x 5.2

aev [14]

Answer:

About 151.500

Step-by-step explanation:

Actual answer is 151.528 Just go with mental math.

8 0

4 years ago

Please I need help urgently

mezya [45]

Answer:

Area = 5(x + 4y - 6).

Step-by-step explanation:

The area of the whole figure = area of rectangle + area of the triangle

= 10(2y - 3) + 1/2 * 10 * x

= 20y - 30 + 5x

= 5(x + 4y - 6).

3 0

3 years ago

What is the axis of symmetry of h(x) = 5x2 40x 64?

kobusy [5.1K]

The axis of symmetry of h(x) = 5x2 + 40x + 64 = -4

The formula for calculating the axis of symmetry is expressed as:

Axis of symmetry x = -b/2a

h(x) = 5x^2 + 40x + 64

a = 5 and b = 40

5 0

2 years ago

Solve −h−7h+13=3. Solve for h

Andreyy89

Answer:

I think your answer is h = -1

6 0

3 years ago

Read 2 more answers

The equation of a circle is x2+y2−12x+6y+20=0 .

Rufina [12.5K]

Answer:

The radius is r=5 units

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

we have

$x^{2}+y^{2}-12x+6y+20=0$

Convert to standard form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$(x^{2}-12x)+(y^{2}+6y)=-20$

Complete the square twice. Remember to balance the equation by adding the same constants to each side

$(x^{2}-12x+36)+(y^{2}+6y+9)=-20+36+9$

$(x^{2}-12x+36)+(y^{2}+6y+9)=25$

Rewrite as perfect squares

$(x-6)^{2}+(y+3)^{2}=5^{2}$

therefore

The center is the point (6,-3) and the radius is r=5 units

8 0

3 years ago