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3 years ago

How Would You Solve (2x+1)(x-5)

Mathematics

2 answers:

Helga [31]3 years ago

6 0

Answer:

2x^2 - 9x - 5

Step-by-step explanation:

This is a multiplication problem; it's not an equation and thus can't be "solved." Rather: "Multiply out (2x+1)(x-5)."

(2x+1)(x-5) = 2x^2 - 10x + x - 5, or 2x^2 - 9x - 5. This is the "product" of (2x+1)(x-5).

matrenka [14]3 years ago

6 0

Answer:

The answers are x = -.5 and x = 5

Step-by-step explanation:

Typically when asked to solve quadratics like this, we are looking for when the equation equals 0. In order to find when the equation is equal to 0, we need to find when each parenthesis is equal to 0.

2x + 1 = 0

2x = -1

x = -.5

x - 5 = 0

x = 5

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Mulitply the binomials and identify the value of "B" in the product. (−2x + 3)(x + 8) = −2x2 −Bx + 24 {"version":"1.1","math":"M

RUDIKE [14]

For
(c+d)(ex+f)
the expanded form is
dex^2+dex+cfx+df
(ce)x^2+(de+cf)x+(df)
ax^2+bx+c
the value of a is ce
the value of b is de+cf
the value of c is df

so

(-2x+3)(x+8)
(-2x+3)(1x+8)
b is 3*1+-2*8=3-16=-13

answer is -13
so pick 13 because we have -B, so B=13

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Mila [183]

Answer:

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3 years ago

Hannah notices that segment HI and segment KL are congruent in the image below: Two triangles are shown, GHI and JKL. G is at ne

BlackZzzverrR [31]

Answer:

segment IG ≅ segment LJ

Step-by-step explanation:

Please refer to the attached image as per the triangles as given in the question statement.

$\triangle HGI, \triangle JKL$

$G\left(-3,1\right),\ H\left(-1,1\right),\ I\left(-2,3\right)$

$J\left(3,3\right),K\left(1,3\right),L\left(2,1\right)$

Given that:

$HI\cong KL$ and

$\angle I \cong \angle L$

<em>SAS congruence </em>between two triangles states that two triangles are congruent if two corresponding sides and the angle between the two sides are congruent.

We are given that one angle and one sides are congruent in the given triangles.

We need to prove that other sides that makes this angle are also congruent.

To show the triangles are congruent i.e. $\triangle GHI \cong \triangle JKL$ by SAS congruence we need to prove that