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anzhelika [568]
3 years ago
8

How Would You Solve (2x+1)(x-5)

Mathematics
2 answers:
Helga [31]3 years ago
6 0

Answer:

2x^2 - 9x - 5

Step-by-step explanation:

This is a multiplication problem; it's not an equation and thus can't be "solved."  Rather:  "Multiply out (2x+1)(x-5)."

(2x+1)(x-5) = 2x^2 - 10x + x - 5, or 2x^2 - 9x - 5.  This is the "product" of (2x+1)(x-5).


matrenka [14]3 years ago
6 0

Answer:

The answers are x = -.5 and x = 5

Step-by-step explanation:

Typically when asked to solve quadratics like this, we are looking for when the equation equals 0. In order to find when the equation is equal to 0, we need to find when each parenthesis is equal to 0.

2x + 1 = 0

2x = -1

x = -.5

x - 5 = 0

x = 5

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