Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
Answer:
The fourth answer choice is the correct one: 2(x - 3)
Step-by-step explanation:
2x²-18x+36/x-6 should be factored, as follows:
2(x²-9x+18) / (x-6) = 2(x - 3) (x - 6) / (x - 6)
Substituting x = 6 would result in division by zero and is thus not allowed.
Remembering this, we can reduce 2(x - 3) (x - 6) / (x - 6) to 2(x - 3) for x≠6.
Answer:
Here you go :)
Step-by-step explanation:
Answer:
f(x) + g(x) = 3x + 7
Step-by-step explanation:
f(x) = 2x + 2, g(x) = x + 5
f(x) + g(x) = 2x + 2 +x + 5
f(x) + g(x) = 2x +x + 5 +2
f(x) + g(x) = 3x + 7
7/16 + 3/8 + Blank = 1
7/16 + 6/16 + 3/16 = 1
convert 3/8 to 6/16 then add 7+6 which = 13
that would be 13/16 then figure out that 13+3 =16 so 13/16+3/16= 16/16 or 1
