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nika2105 [10]
3 years ago
11

Ezra's dad is building a cover for his sandbox. The sandbox is in the shape of a kite as shown. A kite has a width of 6 feet and

a height of 4 feet.' What is the area of the sandbox cover?
Mathematics
1 answer:
Tpy6a [65]3 years ago
5 0

Answer:

Area of the sandbox cover = 12 ft²

Step-by-step explanation:

The area of a kite is given as the product of the two diagonals of the kite divided by 2.

Area of kite = (xy/2)

where x and y are the diagonals of the kite.

The sandbox cover, in shape of a kite has a width of 6 ft and a height of 4 ft.

These two dimensions are the diagonals of the kite. Hence, the area of a kite is

A = (6×4/2) = 12 ft²

Hope this Helps!!!

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Answer:

91.46m

Step-by-step explanation:

The length of 100 yard football field in meters.

From the dimension given,

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100 yard = x feet

X = (100 × 3) / 1

X = 300 feet.

But,

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X metre = 300 feet

X = (300 × 1) / 3.28

X = 91.46m

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Step-by-step explanation:

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Can someone plz help me with 11,12,13 plz show work
dimaraw [331]

Answer:

  11.  x = -3+√37 ≈ 3.08276

  12.  x = 11.2

  13.  x = -6 +6√5 ≈ 7.41641

Step-by-step explanation:

In each case, the relation of interest is ...

  (distance to circle near) × (distance to circle far) = (distance to circle near) × (distance to circle far)

When there is only one point of intersection of the secant with the circle—because it is a tangent—then the product is the square of the length of the tangent.

11. 2(2+12) = x(x +6)

  x² +6x -28 = 0

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  x = -3+√37 ≈ 3.08276

12. 5(5+x) = 9(9)

  5x +25 = 81

  x = 56/5 = 11.2

13. x(x +12) = 12(12)

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  (x +6)² -180 = 0

  x = -6 +√180 ≈ 7.41641

_____

<em>Comment on this secant rule</em>

This rule turns out to apply whether the point of intersection of the secant lines is outside the circle (as in these problems) or inside the circle (as in problem 9). The product of the two distances from the point of intersection to the circle is a constant for a given pair of intersecting secants/chords.

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