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Musya8 [376]
2 years ago
13

The rotation of q h j 180° about the origin

Mathematics
1 answer:
IrinaK [193]2 years ago
7 0
Could you please give me more of a description?
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A local company manufactures netbook computers. Their profit function is given by this equation: y equal minus x to the power of
r-ruslan [8.4K]
The equation described above can also be written as,
                    y = -x² + 100x + 4000
To get the number of notebooks that will give them the maximum profit, we derive the equation and equate to zero.
                  dy/dx = -2x + 100 = 0
The value of x from the equation is 50. Then, we substitute 50 to the original equation to get the profit. 
                   y = -(50^2) + 100(50) + 4000 = 6500
Thus, the maximum profit that the company makes is $6,500/day. 

8 0
2 years ago
Mr. Denning bought a jacket for $67.50
Butoxors [25]

67.50 + 12.50 = 80

80/100 = 0,8 x 3 = 2.4

so, the total bill was 80 + 2.4 = 82.4

<em>hope it helps :)</em>

6 0
3 years ago
Suppose N has a geometric distribution with parameter p. Derive a closed-form expression for E(N | N &lt;= k), k = 1,2,... Check
vfiekz [6]

Answer:

P(X= k) = (1-p)^k-1.p

Step-by-step explanation:

Given that the number of trials is

N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.

Given p = success,

1 - p = failure

Hence the distribution is described as: Pr ( FFFF.....FS)

Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p

Pr((X=k) = (1 - p)^ (k-1) .p

Since N<=k

Pr (X =k) = p(1-p)^k-1, k= 1,2,...k

0, elsewhere

If the probability is defined for Y, the number of failure before a success

Pr (Y= k) = p(1-p)^y......k= 0,1,2,3

0, elsewhere.

Given p= 0.2, k= 3,

P(X= 3) =( 0.2) × (1 - 0.2)²

P(X=3) = 0.128

3 0
3 years ago
If there are 10 billion transistors (each of a square shape) uniformly (without space) distributed on a silicon chip with the sq
Karo-lina-s [1.5K]

Answer:

the transistors have L=1 mm of linear size

Step-by-step explanation:

For the silicon chip the area is A=1 cm² and for the transistors the area is At=L² (L=linear size) . Then since N= 10 billion transistors of area At should fit in the area A

A=N*At

A=N*L²

solving for L

L= √(A/N)

Assuming that 1 billion=10⁹ (short scale version of billion), then

L= √(A/N) = √(1 cm²/10⁹) = 1 cm / 10³ = 1 mm

then the transistors have L=1 mm of linear size

4 0
3 years ago
Pls hurry I’m being
kati45 [8]
D. Warm air rises and cool air sinks
7 0
3 years ago
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