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3 years ago

Extra P./Geometry Help quick! Thanks In Advance :)

Mathematics

1 answer:

IrinaVladis [17]3 years ago

4 0

The measure of angle C is 89 degrees.

Step-by-step explanation:

The given polygon ABCD is a quadrilateral.

The property of a quadrilateral :

The sum of the consecutive angles add to 180°.

In this quadrilateral, the angles B and C are consecutive angles. So, the sum of angle B and angle C is equal to 180 degree.

Given that,

The measure of angle B = 2x+3
The measure of angle C = 2x+1

To find the value of x :

m∠B + m∠C = 180

(2x+3) + (2x+1) = 180

4x + 4 = 180

4x = 180 - 4

4x = 176

x = 176/4

x = 44

To find m∠C :

m∠C = 2x + 1

⇒ 2(44)+1

⇒ 88+1

⇒ 89°

The measure of angle C is 89 degrees.

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3 years ago

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3 years ago

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3 years ago

Read 2 more answers

A potato was launched in the air using a potato gun. The function for the situation was h(t)=-16t^2 +100t+10, where t was the ti

Goshia [24]

Answer:

The height equation is:

h(t)=-16t^2 +100t+10

A) To find the maximum height, we must find the time where the velocity is 0, so we must derive it with respect to the time.

v(t) = -2*16*t + 100 = 0

t = 100/(2*16) = 3.125s

Now we put this time in our height equation:

h(3.125s) = -16*3.125^2 + 100*3.125 + 10 = 166.25 ft.

B) The lowest heigth of the potato will be h = 0ft, when the potato hits the ground.

C) the lowest time that works for that function is t = 0s, when the potato is fired by the gun.

D) the maximum time can be finded when the potato hits the ground, afther that point the equation does not work anymore, let's find it,

h(t) = 0 = -16t^2 +100t+10

we can solve it using Bhaskara's equation:

$t = \frac{-100 +- \sqrt{100^2 +4*16*10} }{-2*16} = \frac{-100 +- 103.2}{-32}$

So the two solutions are:

t = 6.3s

t = -0.1s

We need to chose the positive time, as we already discused that the minimum time that works for the equation is t = 0s.

so here the answer is t = 6.3s

E) the domain is 0s ≤ t ≤ 6.3s

The range is 0ft ≤ h ≤ 166.25 ft.

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3 years ago