What expression is equivalent to 24x - 36 ? A. 2(12x + 18) B. 3(8x + 33) C. 6(4x -6). D. 24(x - 12)
2 answers:
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The price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25
<em><u>Solution:</u></em>
Let d" be the price of 1 drink
Let "p" be the price of 1 pretzel
Given that, Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50
<em><u>Therefore, we can frame a equation as,</u></em>
3 x price of 1 drink + 10 x price of 1 pretzel = 54.50
3d + 10p = 54.5 ---------- eqn 1
Jason went into the same movie theater and bought 9 drinks and 5 pretzels, costing a total of $57.25
9 x price of 1 drink + 5 x price of 1 pretzel = 57.25
9d + 5p = 57.25 ---------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Multiply eqn 1 by 3
9d + 30p = 163.5 ----- eqn 3
<em><u>Subtract eqn 2 from eqn 3</u></em>
9d + 30p = 163.5
9d + 5p = 57.25
( - ) -----------------------
25p = 106.25
p = 4.25
<em><u>Substitute p = 4.25 in eqn 1</u></em>
3d + 10(4.25) = 54.5
3d + 42.5 = 54.5
3d = 54.5 - 42.5
3d = 12
d = 4
Thus price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25
Answer:
20 minutes should spend on walking and 30 minutes on running.
Step-by-step explanation:
Let x represents the minutes spent on walking and y represents the minutes spent on running,
∵ He burns 4 cal/min walking and 10 cal/min running,
So, the total calories burnt,
Z = 4x + 10y
Which has to be maximised.
Now, he walks between 10 and 20 min each day,
i.e. 10 < x < 20,
Also, he runs between 30 and 45 min each day,
i.e. 30 < y < 45,
By graphing 10 < x < 20 and 30 < y < 45,
We obtained the vertices of feasible region,
(10, 45), (20, 45), (10, 30) and (20, 30)
At (10, 45),
Z = 4(10) + 10(45) = 40 + 450 = 490,
At (20, 45),
Z = 4(20) + 10(45) = 80 + 450 = 530,
At (10, 30),
Z = 4(10) + 10(30) = 40 + 300 = 340,
At (20, 30)
Z = 4(20) + 10(30) = 80 + 300 = 380
Hence, maximum calories is 530 when 20 minutes spent on walking and 30 minutes spent on running.
