What are is a most important event in causing geysers

A sample of carbon dioxide has a pressure of 1.2 atm, a volume of

GalinKa [24]

The answer for the following question is mentioned below.

Therefore no of moles present in the gas are 1.12 moles

Explanation:

Given:

Pressure of gas (P) = 1.2 atm

Volume of a gas (V) = 50.0 liters

Temperature (T) =650 K

To calculate:

no of moles present in the gas (n)

We know;

According to the ideal gas equation;

We know;

P × V = n × R × T

where,

P represents pressure of the gas

V represents volume of the gas

n represents no of the moles of a gas

R represents the universal gas constant

where the value of R is 0.0821 L atm mole^{-1} K^-1

T represents the temperature of the gas

As we have to calculate the no of moles of the gas;

n = $\frac{P*V}{R*T}$

n = \frac{1.2*50.0}{0.0821*650}

n = \frac{60}{53.365}

n = 1.12 moles

Therefore no of moles present in the gas are 1.12 moles

3 0

3 years ago

How many moles are in 4.6 x 10^19 atoms? *#27 is the question

velikii [3]

There are 0.000076 moles in 4.6 x 10^19 atoms.

3 0

3 years ago

At a pressure of 782.3 mm Hg and 34.4 °C, a certain gas has a volume of 362.4 mL. What will

german

Answer: v2=331.289mL

Explanation:

Formula for ideal gas law is p1v1/T1=p2v2/T2

P1=782.3mmHg

P2=769mmHg at STP

V1=362.4mL

V2=?

T1=273+34.4=307.4k

T2=273k at STP

Then apply the formula and make v2 the subject of formula

V2= 782.3×362.4×273/760×307.4

V2=77397006.96/233624

V2=331.289mL

7 0

3 years ago

In a chemical reaction, 28g of iron reacts with 16g of sulfur to produce _________ of iron sulfide.

kirill115 [55]

Hello!

In a chemical reaction, 28g of iron reacts with 16g of sulfur to produce _________ of iron sulfide.

We have the following data:

m(Fe) - mass of iron = 28 g

m(S) - mass of sufur = 16 g

MM(Fe) - molar mass of iron ≈ 56 g/mol

MM(S) - molar mass of sulfur ≈ 32 g/mol

n(Fe) - number of mol of iron = ?

n(S) - number of mol of sulfur = ?

Solving:

* to n(Fe)

$n_{Fe} = \dfrac{m_{Fe}}{MM_{Fe}}$

$n_{Fe} = \dfrac{28\:\diagup\!\!\!\!\!g}{56\:\diagup\!\!\!\!\!g/mol}$

$\boxed{n_{Fe} = 0.5\:mol}$

* to n(S)

$n_{S} = \dfrac{m_{S}}{MM_{S}}$

$n_{S} = \dfrac{16\:\diagup\!\!\!\!\!g}{32\:\diagup\!\!\!\!\!g/mol}$

$\boxed{n_{S} = 0.5\:mol}$

The stoichiometric reaction will be in the same proportion (1 : 1), let us see:

$Fe + S \Longrightarrow FeS$

1 mol of Fe -------------- 1 mol of FeS

0.5 mol of Fe ------------ 0.5 mol of FeS

Will the reaction of the iron mass with the mass of sulfur produce how many grams of iron sulfide? We will see:

n(FeS) - number of mol of iron sulfide = 0.5 mol

m(FeS) - mass of iron sulfide = ? (in grams)

MM(FeS) - Molar Mass of iron sulfide = 56 + 32 = 88 g/mol

Solving:

$n_{FeS} = \dfrac{m_{FeS}}{MM_{FeS}}$

$m_{FeS} = n_{FeS}*MM_{FeS}$

$m_{FeS} = 0.5\:mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}*88\:\dfrac{g}{mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}}$

$\boxed{\boxed{m_{FeS} = 44\:g}}\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}$

Answer:

44 grams of iron sulfide

___________________________

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4 0

3 years ago

A rectangular field measures 6.0 m by 8.0 m. What is the area of the field in square centimeters (cm 2 )? Use the formula: Area

Lera25 [3.4K]

The answer is C

6.0m x 8.0m= 48.0m

then converting it to cm by multiply
48 x 100

7 0

3 years ago