N; n + 2 - the two consecutive even integers
n + 3(n + 2) = 46
n + 3n + 6 = 46 <em> |subtract 6 from both sides</em>
4n = 40 <em> |divide both sides by 4</em>
n = 10
n + 2 = 10 + 2 = 12
<u>Answer: 10 and 12.</u>
Answer: 6/12 are white, 3/12 are colored and 3/12 are albino.
Step-by-step explanation: If the horses are white and their parents are ccww (albino) and CCWw (white horse), according to Mendel's premises, they both must be CcWw, since the crossing provides one C from one parent and other c from the other parent, one W and the other w. Using Mendel's chess and the principle of independent segregation, the crossing between CcWw results in the following fenotypical ratio:
1/16 CCWW (lethal)
2/16 CCWw (white)
2/16 CcWW (lethal)
4/16 CcWw (white)
1/16 CCww (normal)
2/16 Ccww (normal)
2/16 ccWw (albino)
1/16 ccWW (lethal)
1/16 ccww (albino)
Excluding the 4 individuals that have the lethal locus, we have 6/12 that are white (2/12 + 4/12) and 3/12 (1/12 + 2/12) that are colored. Also, there are 3/12 of albino individuals as well.
Answer:
B! 
Step-by-step explanation:
Because 10 minus 5 (from the y column) is -5. And -5 - (-2) is +3. So you get -5 over 3 (
). which is B!
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Answer:
35 because they relevantly parrel which explains it alll