Let's first denote the intersection point of diagonals with O. In this parallelogram, we can observe that ΔAOB is congruent to ΔCOD because of AB=CD and the angles ∠BAO and ∠OCD are equal (They are alternate angles). According to the rule of congruency, 3x=4x-5 and x=5
Step-by-step explanation:
1. AB = BC (B is the midpoint of AC)
2. DE = EF (E is the midpoint of DF)
3. EB is common
4. ∠ABE = ∠CBE; ∠BED = ∠BEF (EB⊥AC, EB⊥DF)
5. ΔDEB ≅ ΔFEB (RHS)
6. DB = FB (corresponding ∠s of ≅ Δs)
7. ∠EFB = ∠CBF; ∠EDB = ∠ABD (alternate interior angles, AC║DF)
8. ΔABD ≅ ΔCBF (SAS)
76
100 - 16 = 69 so the x axis would carry the 4 and make it 76
Answer:
On the other equation, there would need to be the point (2, -9)
Step-by-step explanation:
This is because when we find the inverse equations, it is the same as simply switching the x and y values. So in the ordered pair, we would just change the order.
Answer: FIRST OPTION.
Step-by-step explanation:
First, it is important to remember that the Slope-Intercept form of the equation of a line is the shown below:

Where "m" is the slope of the line and "b" is the y-intercept.
By definiton, given a System of Linear equations, if they are exactly the same line, then the System of equations have Infinely many solutions.
In this case you have the following System of Linear equations given in the exercise:

So, since you need the system has Infinite solutions, you know that the slope and the y-intercept of both lines must be equal.
Therefore, you can identify that the value of "a" and "b" must be the following:

So the Linear System would be the shown below:
