Answer:
B
Step-by-step explanation:
Rectangle = 18 x 6 = 108
Circle: 3.14 x (3)^2 = 3.14 x 9 = 28.26
<span>semicircle: 28.26 / 2 = 14.13
</span>
108 + 14.13 = 122.13
answer
122.13 cm^2
Answer:
X = 2 or X = -10
Step-by-step explanation:
We know either3x+12=18or3x+12=−18
3x+12=18(Possibility 1)
3x+12−12=18−12(Subtract 12 from both sides)
3x=6
3x
3
=
6
3
(Divide both sides by 3)
x=2
3x+12=−18(Possibility 2)
3x+12−12=−18−12(Subtract 12 from both sides)
3x=−30
3x
3
=
−30
3
(Divide both sides by 3)
x=−10
Answer:
x=2 or x=−10
Answer:
a) 7/4 b) 5 c) 2
Step-by-step explanation:
Logrithmic Rule for a and b
Let a, M, N be positive real numbers.
a)
logaM - logaN = loga(M/N)
log9(7) - log9(4) = log9 (7/4)
b)
logaM + logaN = logaMN
log2 (x) + log2(9) = log2(45)
x9=45
(x9)/9 = 45/9
x = 5
c)
Change of base formula.
logb(x)=logd(b)/logd(x)
x log6(5) = log6(25) divide each term by log6(5)
x log6(5) / log6(5) = log6(25) / log6(5) Cancel common factor log6(5)
x = log6(25) / log6(5)
x = log6(5^2) / log6(5)
Expand log6(5^2) by moving 2 outside the logarithm.
x = 2log6(5) / log6(5) cancel the like term log6(5)
x = 2
Answer:
1) Event A = 2/3
Event B = 1/2
2) 1/2
Step-by-step explanation:
1)
Event A :
No. we need on dice = 4
Total numbers on dice = 6
Hence sample space of the event = 6
P( getting 4) = 4/6 = 2/3
Event B :
A coin has a head & a tail.
Hence sample space of the event = 2
But as we need tail only ,
P ( getting Tail ) = 1/2 [ if only tossed once ]
2)
Total numbers on a die = 6
Total no. of odd numbers on die = 3 (∵ 1 , 3 & 5 are odd )
Sample space of this event = 6
P (getting an odd number) = 3/6 = 1/2
