A juice drink filling machine, when in perfect adjustment, fills the bottles with 12 ounces of drink on an average. Any overfill
1 answer:
Answer:
d. The average is equal to 12 ounces.
Step-by-step explanation:
In this problem, the drink filling machine must be perfectly calibrated at 12 ounces since it needs to be shut down in cases of overfilling (mean > 12 ounces) and underfilling (mean < 12 ounces). Therefore, the correct approach would be to test if the mean is 12 ounces and the correct set of hypothesis would be:
The correct alternative is d. The average is equal to 12 ounces.
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Answer:
a)
And the margin of error is given by:
The confidence level is 0.96 and the significance level is and the value of
and the margin of error is given by:
We can calculate the critical value and we got:
And if we solve for the deviation like this:
And replacing we got:
b)
And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean
population mean (variable of interest)
represent the population standard deviation
n=80 represent the sample size
Solution to the problem
Part a
The confidence interval for the mean is given by the following formula:
(1)
For this case we can calculate the mean like this:
And the margin of error is given by:
The confidence level is 0.96 and the significance level is and the value of
and the margin of error is given by:
We can calculate the critical value and we got:
And if we solve for the deviation like this:
And replacing we got:
Part b
For this case is the sample size is doubled the margin of error would be:
And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor