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saveliy_v [14]
3 years ago
11

A juice drink filling machine, when in perfect adjustment, fills the bottles with 12 ounces of drink on an average. Any overfill

ing or underfilling results in the shutdown and readjustment of the machine. To determine whether or not the machine is properly adjusted, the correct set of hypotheses isa. The average is greater than or equal to 12 ounces.
b. The average is not equal to 12 ounces.
c. The average is less than 12 ounces.
d. The average is equal to 12 ounces.
Mathematics
1 answer:
ozzi3 years ago
5 0

Answer:

d. The average is equal to 12 ounces.

Step-by-step explanation:

In this problem, the drink filling machine must be perfectly calibrated at 12 ounces since it needs to be shut down in cases of overfilling (mean > 12 ounces) and underfilling (mean < 12 ounces). Therefore, the correct approach would be to test if the mean is 12 ounces and the correct set of hypothesis would be:

H_0:\mu=12\\H_a:\mu\neq 12

The correct alternative is d. The average is equal to 12 ounces.

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The sum of three consecutive numbers is 72 what is the smallest of the numbers
mylen [45]

Answer:

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Step-by-step explanation:

Suppose,

the first number = x

the second number = x+1

the third number = x+1+1 = x+2

Question wise,

x+x+1+x+2 = 72

3x+3 = 72

3x = 72-3 = 69

x = 69/3 = 23

so the numbers are,

23,(23+1)=24 and (23+2)=25

6 0
2 years ago
Three people play a game on each spinner in the previos problem.
arlik [135]

Answer:

Step-by-step explanation:

All other things being equal, spinner A is fine. It is a fair spinner.

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5 0
3 years ago
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Then
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6 0
3 years ago
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Ulleksa [173]

<em>Hey</em><em>!</em><em>!</em><em>!</em><em>!</em>

<em>Here</em><em>'s</em><em> </em><em>you</em><em>r</em><em> </em><em>answer</em><em>:</em>

<em>Sol</em><em>ution</em><em>:</em>

<em>A</em><em>=</em><em>{</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>}</em>

<em>B</em><em>=</em><em>{</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em> </em><em>A</em><em> </em><em>U</em><em> </em><em>B</em><em>=</em><em>{</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>}</em><em> </em><em>U</em><em> </em><em>{</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>{</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em>In</em><em> </em><em>case</em><em> </em><em>of</em><em> </em><em>Union</em><em>,</em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>list</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>elements</em><em> </em><em>which</em><em> </em><em>are</em><em> </em><em>present</em><em> </em><em>in</em><em> </em><em>both</em><em> </em><em>sets</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

4 0
3 years ago
14 more than the prouduct of the three and nine
Varvara68 [4.7K]
41
3 times 9 is 27
27+14=41
5 0
3 years ago
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