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Maslowich
3 years ago
5

What is the following quotient? StartFraction RootIndex 3 StartRoot 60 EndRoot Over RootIndex 3 StartRoot 20 EndRoot EndFraction

Mathematics
2 answers:
FrozenT [24]3 years ago
6 0

Answer:

\sqrt[3]{3}

Step-by-step explanation:

We are required to simplify the quotient: \dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}

Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:

\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}

=\sqrt[3]{3}

The simplified form of the given quotient is \sqrt[3]{3}.

Novosadov [1.4K]3 years ago
5 0

Answer:

A

Step-by-step explanation:

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What is the sum of three consecutive even numbers is 30?
kykrilka [37]
8, 10, 12

A helpful equation:
x+x+1+x+2 = 30

Combine like terms
3x + 3 = 30

Subtract 3 from each side
3x = 27

Divide each side by to isolate x
x = 9

x = 9. However, 9 is not an even number. Let’s subtract 1 from 9 to get the first even number.

The first number is 8. The best two even numbers after 8 are 10 and 12.

8 + 10 + 12 = 30, thus this is the sequence.
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3 years ago
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What r the answers to these questions(picture above)?PLEASE HELP
kirill [66]

Problem 3

The constant term is 290. This is the term that stays the same no matter what the value of 'a' happens to be. Contrast this with the variable term 2.50a which changes if 'a' changes (hence the name "variable" for "vary" or "change")

If Mike sold 0 accessories, then a = 0 and the expression would be

2.50*a + 290 = 2.50*0 + 290 = 290

Selling 0 accessories leads to $290. This is the amount he is guaranteed with the 2.50a portion being additional money to motivate him to sell more.

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Answer: Choice (3) 290, amount he is guaranteed

======================================

Problem 4

Plug y = 0 into the equation. Solve for x

9x - 14y = -3

9x - 14*0 = -3 .... replace y with 0

9x - 0 = -3

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6 0
3 years ago
The fox population in a certain region has a continuous growth rate of 5% per year. It is estimated that the population in the y
kvasek [131]

Answer:

P(t) = A * (1 + r)^t ;

14,922 ;

Year 2013

Step-by-step explanation:

Given the following :

Continuous growth rate(r) = 5% = 0.05

Population in year 2000 = Initial population (A) = 10,100

Time(t) = period (years since year 2000)

A)

Find a function that models the population,P(t) , after (t) years since year 2000 (i.e. t= 0 for the year 2000).

P(t) = A * (1 + r)^t

Trying out our function for t = year 2000, t =0

P(0) = 10,100 * (1 + 0.05)^0

P(0) = 10,100 * 1.05^0 = 10,100

B.)

Use your function from part (a) to estimate the fox population in the year 2008.

Year 2008, t = 8

P(8) = 10,100 * (1 + 0.05)^8

P(8) = 10,100 * 1. 05^8

P(8) = 10,100 * 1.4774554437890625

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P(t) = A * (1 + r)^t

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18400/10100 = 1.05^t

1.8217821 = 1.05^t

1.05^t = 1.8217821

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DerKrebs [107]

Answer:

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Step-by-step explanation:

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3 years ago
Use the discriminant to determine the number of real solutions to the equation,<br> 10n^2 = 10 - 8n
galben [10]

Answer:

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Step-by-step explanation:

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b^2 -4ac

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