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raketka [301]
3 years ago
10

Can anyone evaluate this problem for me .

Mathematics
2 answers:
Nostrana [21]3 years ago
8 0

Answer:

-4

Explanation: You do all of the parenthesis right to left first and then do the 1 in the middle, then evaluate the rest of the equation.

AURORKA [14]3 years ago
5 0

Answer:

s

Step-by-step explanation:

s

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A recent survey found that 65% of high school students were currently enrolled in a math class, 43% were currently enrolled in a
Bas_tet [7]
<h3>Answer: Choice A)  0.20</h3>

===================================================

Explanation:

Let's say there are 1000 students. The students must take math, science or they can take both simultaneously.

  • 65% of them are in math. So there are 0.65*1000 = 650 math students.
  • 43% are in science, leading to 0.43*1000 = 430 science students.
  • 13% are in both so we have 0.13*1000 = 130 students who are in both.

Now onto the sentence that says "Suppose a high school student who is enrolled in a math class is selected at random"

This means we only focus on the 650 math students and ignore the 1000-650 = 350 students who aren't in math.

Of those 650 math students, 130 are also in science (since 130 are in both classes).

The probability we're after is therefore 130/650 = 0.20

4 0
3 years ago
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The sum of the first 150 negative integers is represented using the expression What is the sum of the first 150 negative integer
Kamila [148]

Answer:

C. -11,325

Step-by-step explanation:

  • To know the answer, is convenient to replace some values of "n" in the sum \sum_{(n=1)}^{150}[-1-(n-1)].
  • The result would appear after adding up every value of the expression \sum_{(n=1)}^{150}[-1-(n-1)] when n=1,2,3.....,150.
  • When n=1, the expression takes the value of (-1): [-1-(1-1)]= (-1)-0=-1.
  • When n=2, the expression takes the value of (-2): [-1-(2-1)]=-1-1=-2.
  • Following this way, for every n, we will obtain -n, then, the sum will be: -1-2-3-4-5-6-...-150. This sum can actually be expressed as \sum_{n=1}^{150}(-n), which is the result of solving the initial expression of the sum -1-(n-1)=-1-n+1=-n.
  • Finally, the sum of n=-1 to n=-150 equals -11,325.
7 0
4 years ago
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The probability that Ariana is on time for a given class is 69 percent. If there are 39 classes during the semester, what is the
salantis [7]

Answer:

The best estimate of the number of times out of 39 that Ariana is on time to class is 27.

Step-by-step explanation:

For each class, there are only two possible outcomes. Either Ariana is on time, or she is not. The probability of Ariana being on time for a class is independent of other classes. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The probability that Ariana is on time for a given class is 69 percent.

This means that p = 0.69

If there are 39 classes during the semester, what is the best estimate of the number of times out of 39 that Ariana is on time to class

This is E(X) when n = 39. So

E(X) = np = 39*0.69 = 26.91

Rounding

The best estimate of the number of times out of 39 that Ariana is on time to class is 27.

8 0
3 years ago
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