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4 years ago

HELP PLEASE!! I NEED HELP ASAP

Mathematics

1 answer:

marysya [2.9K]4 years ago

4 0

Answer:

3. A

4. B

5. C

6. A

7. D

Step-by-step explanation:

It is easy you just need to be paying attention in class then you will get it. I used to go on Brainly for people to do my homework but it is no worth it. you need to try it on your own. When you turn it in and you get it all correct and you get an A. You are just checking yourself.

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How do we convert kilogram to gram

Sloan [31]

7kg*1000=7000g

10kg*1000=10000g

15g*1000=15000g

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3 years ago

10>x/3+6 help me please

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Minus 6 both sides
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times3 both sides
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3 years ago

Read 2 more answers

If a triangle has an area of 192 mm2, and the

Debora [2.8K]

Answer:32mm

Step-by-step explanation:

area of triangle = 1/2 *base * height

192mm2 = 1/2 *b* 12mm

192 =6b

base=192/6

base= 32mm

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3 years ago

Select the statement that is false.

defon

Answer:

number 3 is incorrect the rest are correct

7 0

3 years ago

A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi

Margaret [11]

Answer:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=26Kg$

Step-by-step explanation:

Data

Brine a (Ba)

$V_{Ba}=5\frac{Lt}{min}\\ Concentration(Bca)=0.05\frac{Kg}{Lt}$

Brine b (Bb)

$V_{Bb}=10\frac{Lt}{min}\\ Concentration(Bcb)=0.04\frac{Kg}{Lt}$

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: $y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}$

Finally:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=0.65\frac{Kg}{min}(40min)=26Kg$

being y(t) the amount of salt (y) per unit of time (t)

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3 years ago