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Dmitry_Shevchenko [17]
3 years ago
5

Help give right answer

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
4 0
Perimeter is the distance around a shape. You add all of the lengths to get the perimeter.

3 1/10 + 4 7/20 + 5 9/10 + 4 7/20 = 17 7/10.

This could be wrong — sorry in advance if it is.
You might be interested in
David has $9.39 but needs $15.00 to make a purchase. How much more does he need?
elena-14-01-66 [18.8K]

Answer:

$5.61

Step-by-step explanation:

Since David only has $9.39 but he needs $15.00 for his purchase. So, you would subtract the $9.39 from the $15.00 to see how much more money David needs to make this purchase.

15.00 - 9.39

When you carry out this problem, it equals $5.61.

Therefore, David needs $5.61 to be able to complete his purchase

8 0
3 years ago
2 Points
pav-90 [236]
Subtract 15 from both sides.
28-15=13
X=13
7 0
3 years ago
A theater has 60 seats on the front row. There are seven additional seats in each following row.
maksim [4K]

Answer:

(a) y(x)=53+7x

(b) 179

Step-by-step explanation:

Since the first row has 60 seats and next row has 7 additional seats then we can represent it as

First row=60

Second row=60+7=67

Third row=67+7=74

The difference is always 7. If you deduct 7 from dirst row we get 60-7=53 seats

To get rhe number of seats in any row x then let y be the number of seats in row x

y=53+7(x)

For raw 1

Y=53+7(1)=60

For raw 2

Y=53+7(2)=67

Therefore, the formula for number of seats at any row will be

y(x)=53+7(x)

(b)

Using the above formula

y(x)=53+7(x)

Replace x with 18 hence

Y(18)=53+7*(18)=179 seats

5 0
3 years ago
Mr Tay had 265 m of wire.
Ahat [919]

Answer:6

Step-by-step explanation:

265-25

240/4

6

8 0
3 years ago
Read 2 more answers
What are all the exact solutions of -3tan^2(x)+1=0? Give your answer in radians.
goldenfox [79]
   
\displaystyle\\
 -3\tan^2x + 1 = 0\\\\
 -3\tan^2x = -1\\\\
\tan^2x =  \frac{-1}{-3} \\\\
\tan^2x =  \frac{1}{3} ~~~~~ \Big|~\sqrt{~~~} \\\\
\sqrt{\tan^2x} =  \sqrt{\frac{1}{3}} \\\\
\tan x = \Big| \frac{1}{ \sqrt{3} } \Big|\\\\
\tan x = \Big| \frac{\sqrt{3}}{ 3 } \Big|\\\\
\tan x =  \frac{\sqrt{3}}{ 3 }~~~\Longrightarrow~~x_1=  \frac{\pi}{6} + k\pi,~~k \in N \\\\  
\tan x =  -\frac{\sqrt{3}}{ 3 }~~~\Longrightarrow~~x_2=  \pi-\frac{\pi}{6} + k\pi = \frac{5\pi}{6} + k\pi,~~k \in N \\\\  




4 0
3 years ago
Read 2 more answers
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