Let X = smallest angle
largest 3x
middle=2x. add the 3 angles of any triangle and you get ,180
x+2x+3x=180
6x=180
x= 30
smallest =30
middle=60
largest=90
Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data, 
= 5.5 mins
Standard deviation, 
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒ 
...raw score,
= 
⇒ Plugging the values.
⇒ 
⇒ 
For raw score 5.5 the z score is.
⇒ 
⇒ 
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒ 
⇒ 
and 
.<em>..from z -score table.</em>
⇒ 
⇒ 
To find the percentage we have to multiply with 100.
⇒ 
⇒ 
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
Answer:
1/5
Step-by-step explanation:
<u>silk butterfly = 4cm=1 </u> (this is the reduce form )
butterfly 20cm=5
Also you will just divide this by 4
Lets be a price of the calculator - $ a
then , after using the coupon, you need to pay $(a-18)
and after using 15% discount , you need to pay (1-0.15)a=0.85a
then, if
(a-18) will be more than 0.85a, you should prefer 0.15 % discount, because it will be cheaper,
a-18> 0.85a
a-0.85a>18
0.15a > 18
a>120, that means that if the price of the calculator more than $120, 15% discount is better,
but if the price of the calculator is less than $120, you should choose $ 18 coupon.
for example, we have the price of the calculator $100
100-18=82,
100*0.85 =85, coupon is better.
If the price of the calculator $200
200-18=182,
200*0.85=170, so 15% discount is better
if price of the calculator is $120,
120-18=102
120*0.85=102,
it will not matter, what you are going to use, because you are going to pay the same amount of money
Answer:
11.75 years
Step-by-step explanation:
If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...
P(z ≤ -6) ≈ 9.86588×10^-10
and
P(z ≤ -4.5) ≈ 3.39767×10^-6
the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:
0.50^t = 0.000290372
t·log(0.50) = log(0.00290372) . . . . take logarithms
t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030
t ≈ 11.75
It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).
_____
<em>Comment on Six Sigma</em>
A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.
Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.
Then the improvement ratio needs to be only 0.00251699, and it will take only about ...
t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years
