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Dmitry_Shevchenko [17]
3 years ago
5

Help give right answer

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
4 0
Perimeter is the distance around a shape. You add all of the lengths to get the perimeter.

3 1/10 + 4 7/20 + 5 9/10 + 4 7/20 = 17 7/10.

This could be wrong — sorry in advance if it is.
You might be interested in
The largest angle in a triangle is three times as big as the smallest angle, and the middle angle is twice as big as the smalles
PtichkaEL [24]
Let X = smallest angle
largest 3x
middle=2x. add the 3 angles of any triangle and you get ,180

x+2x+3x=180
6x=180
x= 30
smallest =30
middle=60
largest=90
8 0
2 years ago
Assume the hold time of callers to a cable company is normally distributed with a mean of 5.5 minutes and a standard deviation o
Ierofanga [76]

Answer:

The percent of callers are 37.21 who are on hold.

Step-by-step explanation:

Given:

A normally distributed data.

Mean of the data, \mu = 5.5 mins

Standard deviation, \sigma = 0.4 mins

We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.

Lets find z-score on each raw score.

⇒ z_1=\frac{x_1-\mu}{\sigma}   ...raw score,x_1 = 5.4

⇒ Plugging the values.

⇒ z_1=\frac{5.4-5.5}{0.4}

⇒ z_1=-0.25  

For raw score 5.5 the z score is.

⇒ z_2=\frac{5.8-5.5}{0.4}  

⇒ z_2=0.75

Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.

We have to work with P(5.4<z<5.8).

⇒ P(5.4

⇒ P(-0.25

⇒ P(z

⇒ z(1.5)=0.7734 and z(-0.25)=0.4013.<em>..from z -score table.</em>

⇒ 0.7734-0.4013

⇒ 0.3721

To find the percentage we have to multiply with 100.

⇒ 0.3721\times 100

⇒ 37.21 %

The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21

4 0
2 years ago
See photo PLEASE HELP:(
slega [8]

Answer:

1/5

Step-by-step explanation:

<u>silk butterfly =    4cm=1 </u>  (this is the reduce form )

butterfly            20cm=5            

                                                           Also you will just divide this by 4

8 0
3 years ago
Helppppp god bless u
Vanyuwa [196]
Lets be a price of the calculator - $ a
then , after using the coupon, you need to pay $(a-18)
and after using 15% discount , you need to pay (1-0.15)a=0.85a

then, if 
(a-18) will be more than 0.85a, you should prefer 0.15 % discount, because it will be cheaper,

a-18> 0.85a
a-0.85a>18
0.15a > 18
a>120, that means that if the price of the calculator more than $120, 15% discount is better,
but if the price of the calculator is less than $120, you should choose $ 18 coupon.

for example, we have the price of the calculator $100
100-18=82,
100*0.85 =85, coupon is better.

If the price of the calculator $200
200-18=182,
200*0.85=170, so 15% discount is better

if price of the calculator is $120,
120-18=102
120*0.85=102, 
it will not matter, what you are going to use, because you are going to pay the same amount of money





5 0
3 years ago
Read 2 more answers
Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

  t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
3 years ago
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