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morpeh [17]
3 years ago
8

You've decided to take up kayaking. You can either buy your kayak for $197 and pay $8 every time you launch it or you can rent a

kayak for a one time fee of a $10 security deposit and pay $25 per launch. After how many days/launches will it not matter whether you rent or buy? Assume you only kayak once a day
Mathematics
1 answer:
kari74 [83]3 years ago
5 0

Answer:

12 launches

Step-by-step explanation:

Let's represent this with two equations, with C(r) representing cost of buying, x representing each day you launch, C(r) representing cost of renting.

Cost of buying = 197 + 8x

C(b) = 198 + 8x

Cost of renting = 10 + 25x

C(r) = 10 + 25x

The question asks us when it will not matter. This means that we want to find when the cost is equal for renting and buying. So set these equations equal:

198 + 8x = 10 + 25x

Subtract 10 from both sides:

188 + 8x = 25x

Subtract 8x from both sides:

188 = 17x

Divide both sides by 17:

188/17 = x

x = 11.06, round this up to 12 days. (At the 11th day, it still matters.)

<u>It will not matter after 12 launches.</u>

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if the class charges $15 per ticket write an equation that could be used to determine the number of tickets the class would need
OverLord2011 [107]

t = number of tickets

15t ≥ 1500

so....

step 1. 15t ≥ 1500 --> divide both sides by 15 --> 15t/15 ≥ 1500/15

step 2. t ≥ 100


So 100 at the least, ticket should be sold to reach atleast $1500.


I hope this helps. :)



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4 years ago
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aleksandr82 [10.1K]

Answer:

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Step-by-step explanation:

5x x -23 +45

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abruzzese [7]

Answer:

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Step-by-step explanation:

outside the circles contain probability of neither red, cool and water proof. where the circles intersect shows probability of both either red and cool, water proof and cool and water proof and red etc. where all the circles intersect if for the three combinations which is nill. Attached is the diagram

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