X/4 = 2.....x = 8
x - 9 = 17....x = 26 <=== there is the odd ball
x + 12 = 20....x = 8
2x = 16....x = 8
The two real values that are not in the domain of the composition are x = 2 and x = -2.
<h3>
What two numbers are not in the domain of f°g?</h3>
Here we have:
f(x) = 1/x
g(x) = x^2 - 4
The composition is:
f°g = f(g(x)) = 1/(x^2 - 4)
The two values that are not in the domain are the values of x such that g(x) = 0, because we can't divide by zero.
g(x) = 0 = x^2 - 4
4 = x^2
±√4 = x
±2 = x
So g(x) = 0 when x = 2 or x = -2, so these are the two real values that are not in the domain of f°g.
If you want to learn more about domains:
brainly.com/question/1770447
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Answer:
mhm
Step-by-step explanation:kk
This equation simplified would be 2x^2.
Since we have terms that are not like (one has a variable and the other doesn't), we simply put them together when being multiplied.
x^2 * 2 = 2x^2
Answer:
Each of the 5 children receive one fifteenth pie
Step-by-step explanation:
Given:
One third of a pie shared equally between 5 children.
To find:
Amount of the pie with each of the 5 children.
Solution:
Number of children = 5
Also, one third of a pie shared equally between 5 children.
So,
Amount of the pie with each of the 5 children 
Hence, each of the 5 children receive one fifteenth pie.
