To solve for the surface area of the pyramid, we make use
of the formula:
A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))
where,
l and w are the base of the pyramid = 100 mm
h is the height of the pyramid = 75 mm
Substituting the given values into the equation:
A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100
/ 2)^2 + 75^2))
A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)
A = 20,148.90 mm^2
Therefore the surface area of the pyramid is about 20,149
mm^2.
Answer: 42.25 feet
Step-by-step explanation:
We know that after "t" seconds, its height "h" in feet is given by this function:
The maximum height is the y-coordinate of the vertex of the parabola. Then, we can use the following formula to find the corresponding value of "t" (which is the x-coordinate of the vertex):
In this case:
Substituting values, we get :
Substituting this value into the function to find the maximum height the ball will reach, we get:
You would start at (0,36) and then move to (1, 24) , (2,12), (3,0) because he gives out 12 bags per hour
Answer:
B: Negative
Step-by-step explanation:
-2/1 is the slope which is negative.