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kirza4 [7]
3 years ago
13

Question 1Is the expression x^3*x^3*x^3equivalent to x^(3*3*3)? Why or why not? Explain your reasoning.No because the law of exp

onentsQuestion 2Rewrite in simplest radical form1/x^((-3)/6)Show each step of your process.Question 3Rewrite in simplest rational exponent form √x • 4√x. Show each step of your process.Question 4Rewrite in simplest radical formx^(5/6)/x^(1/6)Show each step of your process.Question 5Which of the following expressions are equivalent? Justify your reasoning.4√x31/x^(-1)10√x5•x4•x2x^(1/3)*x^(1/3)*x^(1/3)
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
5 0

Answer: Question 1) No, because according to the law of exponents

x³.x³.x³ = x³⁺³⁺³ = x⁹

and x⁽³*³*³⁾ = x²⁷

Question 2) √x

Question 3) 4x

Question 4) ∛x²

Question 5) B = D

Step-by-step explanation:

Question 1) Is the expression x^3*x^3*x^3 equivalent to x^(3*3*3)? Why or why not? Explain your reasoning.

No, because according to the law of exponents

x³.x³.x³ = x³⁺³⁺³ = x⁹

and x⁽³*³*³⁾ = x²⁷

Question 2) Rewrite in simplest radical form 1/x^((-3)/6). Show each step of your process.

simplifying the denominator expoent: 1/x^((-3)/6) = 1/x^(-1/2)

apply the expoent to the hole fraction: 1/x^(-1/2) = (1/x)^(-1/2)

changing the signal on the expoent: (1/x)^(-1/2)  = (x)^(1/2)

changing the expoent into root: (x)^(1/2) = √x

1/x^((-3)/6) = 1/x^(-1/2) = (1/x)^(-1/2) = (x)^(1/2) = √x

Question 3) Rewrite in simplest rational exponent form √x • 4√x. Show each step of your process.

√x • 4√x = 4√x • √x = 4√x² = 4x

Question 4) Rewrite in simplest radical formx^(5/6)/x^(1/6). Show each step of your process.

x^⁽⁵/⁶⁾/x^⁽¹/₆⁾ = x^⁽⁵/⁶⁾ • 1/x^⁽¹/₆⁾ = x^⁽⁵/⁶⁾ • x^⁽⁻¹/₆⁾ = x^⁽⁵/⁶ ⁻ ¹/⁶) = x^⁽⁴/⁶⁾ = x^⁽²/₃⁾ = ∛x²

Question 5) Which of the following expressions are equivalent? Justify your reasoning.

A. ⁴√x³    B. 1/x⁻¹    C. ¹⁰√x⁵•x⁴•x²     D. x¹/³•x¹/³•x¹/³

A. ⁴√x³ = x³/⁴

B. 1/x⁻¹ = (1/x)⁻¹ = x

C. ¹⁰√x⁵•x⁴•x² = ¹⁰√x¹¹ = x¹¹/¹⁰

D. x¹/³•x¹/³•x¹/³ = x⁽¹/³⁺¹/³⁺¹/³⁾ = x³/³ = x

So, B = D

You might be interested in
In the diagram below AE = 6, EB = 3, and DE = 2. Find CE
cluponka [151]

Theorem: If two chords intersect within a circle, then the product of the lengths of the segments (parts) of one chord is equal to the product of the lengths of the segments of the other chord.

In your case,

AE\cdot EB=CE\cdot ED.

If AE = 6, EB = 3, and DE = 2, then

6\cdot 3=CE\cdot 2,\\ \\CE=\dfrac{6\cdot 3}{2}=9.

Answer: correct choice is D.

4 0
3 years ago
The triangles are isosceles and ΔABC : ΔJKL. What is the length of pie?<br>A=2.5cm<br>C=4cm<br>k=5cm
Pavlova-9 [17]
The length of the pie is 20cm2
6 0
3 years ago
Li’s garden is shaped like a rectangle. The area of the garden is 232 meters. If the length is 8 meters, what is the perimeter?
Serggg [28]

Answer: 29 m

Step-by-step explanation: First find the width

Since Area = Length x Width

Width = Area/Length = 232/8 = 29

Please mark as the brainliest! Thanks!

4 0
3 years ago
Nadia says the hypotenuse of the right triangle has a length of 73 because the Pythagorean theorem states that (28+45)squared eq
Setler79 [48]

Answer: Her solution is incorrect. The hypotenuse is 53 units

Step-by-step explanation: The error occurred when she quoted the Pythagorean theorem. She added up both sides and squared them and made the answer equal to the square of the hypotenuse. She was supposed to have squared them first, before adding up.

The Pythagorean (or Pythagoras) theorem states that the sum of the squares of two sides of a right angled triangle equals the square of the hypotenuse of the triangle. That is, in triangle ABC, if the hypotenuse is given as line AC, the Pythagoras theorem states that

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse and AB and BC are the other two sides.

In Nadia’s solution, if the hypotenuse is given as 73, and the other two sides are 28 and 45, then the Pythagorean theorem properly expressed would be as follows;

73^2 = 28^2 + 45^2

5329 = 784 + 2025

5329 ≠ 2809

As we have determined, writing out the expression as

73^2 = (28 + 45)^2 is very incorrect as this is not the Pythagorean theorem and of course, the triangle cannot have 73 as its hypotenuse as we have determined by properly writing out the Pythagorean theorem.

The correct solution is as follows;

AC^2 = AB^2 + BC^2

AC^2 = 28^2 + 45^2

AC^2 = 784 + 2025

AC^2 = 2809

Add the square root sign to both sides of the equation

AC = 53

Therefore, the hypotenuse is 53 units

4 0
3 years ago
Read 2 more answers
Find the GCF
Kaylis [27]
Greatest Common Factor. let's go over that. GCF of 6 and 12 would be 6 because 6 goes into 6, 1 times and 6 goes into 12, 2 times. . and it is the largest. so first you see if the lower number can go directly into the higher number. So 28a^2 b^2 c^2, is made of 14abc× 2abc. so you can say 14abc goes into 28a2b2c2, 2abc times. therefore 14abc is the largest factor.
7 0
3 years ago
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