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Natali [406]
2 years ago
13

Sara and ava are taking a roadtrip that is 181.40.Sara drove 3/4 of the total distance. How many miles did sara drove?

Mathematics
1 answer:
Katen [24]2 years ago
4 0
136.05 miles 181.4/4x3=136.05
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Find the number that makes the ratio equivalent to 1:2.<br> 8:
Ksju [112]

Answer:

16

Step-by-step explanation:

1/2 is equal to 8/16

8 0
3 years ago
Izzys dog is 10 1/2 years old. Car end dog is 18 months old. How many years older is Izzys dog.
dsp73
12 months in a year. So 18 months= 1 year and 6 months. Izzys dog is 10 1/2= 10 years and six months. Then subtract 1 year and 6 months by 10 year and six months and it would be exactly 9 years older.
6 0
3 years ago
Graph the function y = 4 . Then use the graph to find the missing x- or y-coordinates for the function to the nearest hundredth.
Elodia [21]

Given equation is y=4.

Question says to graph the given equation y=4 then use the graph to find the missing x- or y-coordinates for the function to the nearest hundredth.

Equation y=4 has no "x" so that means line y=4 will be a horizontal line which passes through 4 on y-axis.

Since it is parallel to x-axis so that means there is no x-intercept.

y-intercept is (0,4) as the line crosses at 4 on y-axis.


5 0
3 years ago
The width of a rectangle is 8y- 1.5 feet and the length is 1.5y+9 feet. Find the perimeter of the rectangle.
lyudmila [28]

Answer:

P=19y+15

Step-by-step explanation:

Step one:

Given data

dimension of the rectangle

Width = 8y-1.5

Length = 1.5y+9

Required

The expression to represents the Perimeter

Step two:

the perimeter of  a rectangle is expressed as

P= 2L+2W\\\\P=2(1.5y+9)+2(8y-1.5)\\\\P=3y+18+16y-3\\\\

collect like terms

P=3y+16y+18-3\\\\P=19y+15

6 0
3 years ago
Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui
Vesnalui [34]
<h3>The dimensions of the given rectangular box are:</h3><h3>L  =   15.874 cm  , B  =  15.874 cm   , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box  

= Area of the base +  4 x ( Area of the adjacent faces)

=  S x S  +  4 ( S x H)   = S² +  4 SH   ..... (1)

Also, Area of the box  = S x S x H  =  S²H

⇒ S²H = 2000

\implies H = \frac{2000}{S^2}

Substituting the value of H in (1), we get:

A = S^2 + 4 SH =  S^2 + 4 S(\frac{2000}{S^2}) =  S^2 + (\frac{8000}{S})\\\implies A  =  S^2 + (\frac{8000}{S})

Now, to minimize the area put :

(\frac{dA}{dS} ) = 0 \implies 2S  - \frac{8000}{S^2}  = 0\\\implies S^3 = 4000\\\implies S  = 15.874 \approx 16 cm

Putting the value of S  = 15.874 cm in the value of H , we get:

\implies H = \frac{2000}{S^2}  =  \frac{2000}{(15.874)^2} = 7.8937 cm

Hence, the dimensions of the given rectangular box are:

L  =   15.874 cm

B  = 15.874 cm

H = 7.8937 cm

3 0
3 years ago
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