Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
Part 1) Find the area
we know that
The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle
so

we have that the base and the height of triangle is equal to the radius of the circle

substitute

simplify
Factor 36

Part 2) Find the perimeter
The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle
The circumference of a quarter of circle is equal to

substitute the given values

Applying the Pythagorean Theorem
The hypotenuse of right triangle is equal to

simplify

Find the perimeter

simplify
Factor 6

Answer:


Step-by-step explanation:
Given

Required
Solve:

Open bracket

Take LCM



Take LCM


Divide by 3/3

Answer:
depends on what the price of the bicycle is and the discount percentage
Step-by-step explanation:
It is parallel to the third side and has a length equal to half the length of the third side.
so
x= 34/2= 17
x= 17