So let f(x) = x^(2/3)
<span>Then let f'(x) = 2/3 x^(-1/3) = 2 / (3x^(1/3)) </span>
<span>When x = 8, </span>
<span>f(8) = 8^(2/3) = 4 </span>
<span>f'(8) = 2 / (3*8^(1/3)) = 1/3 </span>
<span>So near x = 8, the linear approximation is </span>
<span>f(x) ≈ f(8) + f'(8) (x - 8) </span>
<span>f(x) ≈ 4 + 1/3 (x - 8) </span>
<span>So the linear approximation for x = 8.03 is... </span>
<span>f(8.03) ≈ 4 + 1/3 (8.03 - 8) </span>
<span>f(8.03) ≈ 4 + 1/3 (0.03) </span>
<span>f(8.03) ≈ 4.01 </span>
<span>8.03^(2/3) ≈ 4.01 </span>
Answer:
x = 15
Step-by-step explanation:
Hope this helps! :D
If Joe collected 94 stamps which are in April May and June, we could make an equation like this: A + M + J = All stamps
Plug in the values:
Isolate J:
Combine like terms:
He collected 33 stamps in June.
You can use the Law of Cosines, if only one of which is missing: three sides and one angle. Hence, if the known properties of the triangle is SSS(side-side-side) or SAS (side-angle-side), this law is applicable.
You can use the Law of Sines if you want to equate the ratio of the sine of an angle and its opposite side. This can be used if the known properties of the triangle is ASA(angle-side-angle) or SAS.
The ambiguous case is the SAS triangle. This could be easily solved using Law of Sines than Law of Cosines. Take for example: side a = 4, side b = 10, angle A = 23°. Then, we can determine angle B through Sine Law.
sin 23°/4 = sin B/10
B = 77.64°
Answer:
9.9
Step-by-step explanation:
