<span>Hint: Remember that the length of AC = length of CD. This is because they are both radii of the same circle. Therefore, Triangle ACD is an equilateral triangle, with angle(ACD)=angle(CAD)=25degrees.
From there, we can work out the angle of ADC: 180-25-25=130 degrees.
Now, expand our scope, and look at the quadrilateral ABCD. We have two right angles in this quadrilateral, because of the tangency of two of the sides with the circle. So to work out the required angle(ABC), just take subtract 2*90degrees and angle(ADC)=130deg from 360deg (which is the sum of all angles of a quadrilateral. Then we have the answer: 50degrees</span>
Any of the 11 man can be chosen, and combined with any of the 8 women.
Assume we select man1. The selected committee can be:
(m1,w1), (m1,w2), (m1,w3), (m1,w4), (m1,w5), (m1,w6), (m1,w7), (m1,w8),
so there are 8 committees selections with man1 in them.
we could repeat the same procedure for the remaining 10 men, and get 8 committees where each of them is a member.
so there are 11*8=88 ways of choosing 1 man and 1 woman.
Answer: 88
Answer:
3/10 is bigger
Step-by-step explanation:
<em>covert </em>into a decimal so 0.3 is bigger than 0.2857
Answer:
The answer is H or J either those two and I'm sure of it.
Step-by-step explanation:
;)
Answer:
the answer is from the given replacement is 4
