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murzikaleks [220]
3 years ago
10

BRAINLIEST QUESTION

Mathematics
1 answer:
Debora [2.8K]3 years ago
6 0

Answer:

the answer is triangles ABC and DEC are similar

Step-by-step explanation:

angle C is a common angle for both triangles

angle D is equal to angle A ( corresponding angles)since they are parallel

angle B is also equal to angle B for the same reason as angle D and A

since the three angles of the two angles are equal they are similar

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Karina bought 4 packages of the type of gum shown.
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Step-by-step explanation:4n+3=60

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2 years ago
What is true of the graph of two lines 3y-8=-5x and 6y=-10x+16
Murljashka [212]

Answer:

Both lines are equal (they are the same)

<em></em>

Step-by-step explanation:

Given

3y - 8 = -5x

6y = -10x + 16

Required

What is true about graph of both lines

<em>Questions like this are better solved when there's option(s) to select from. However, some of the properties of line equation that I'll consider are to check  if both lines are either parallel or perpendicular</em>

<em />

To do this,

The first thing to do is to calculate the slope of both lines

3y - 8 = -5x

Add 8 to both sides

3y - 8 + 8 = -5x + 8

3y = -5x + 8

Divide both sided by 3

\frac{3y}{3} = -\frac{5x}{3} + \frac{8}{3}

y = -\frac{5x}{3} + \frac{8}{3}

The slope of the line is the coefficient of x;

Slope = -\frac{5}{3}

Solve for the y intercept; <em>Let x = 0</em>

y = -\frac{5 * 0}{3} + \frac{8}{3}

y = 0 + \frac{8}{3}

y = \frac{8}{3}

Solve for the x intercept; <em>Let y = 0</em>

0 = -\frac{5x}{3} + \frac{8}{3}

Subtract \frac{8}{3} from both sides

0 - \frac{8}{3} = -\frac{5x}{3} + \frac{8}{3} - \frac{8}{3}

- \frac{8}{3} = -\frac{5x}{3}

Subtract both sides by -\frac{3}{5}

-\frac{3}{5}*- \frac{8}{3} = -\frac{5x}{3} * -\frac{3}{5}

-\frac{3}{5}*- \frac{8}{3} = x

\frac{3}{5} * \frac{8}{3} = x

\frac{8}{5} = x

x = \frac{8}{5}

------------------------------------------------------------------------------------------------------

6y = -10x + 16

Divide both sides by 6

\frac{6y}{6} = -\frac{10x}{6} + \frac{16}{6}

y = -\frac{10x}{6} + \frac{16}{6}

Simplify fractions to lowest term

y = -\frac{5x}{3} + \frac{8}{3}

The slope of the line is the coefficient of x;

Slope = -\frac{5}{3}

Solve for the y intercept; <em>Let x = 0</em>

y = -\frac{5 * 0}{3} + \frac{8}{3}

y = 0 + \frac{8}{3}

y = \frac{8}{3}

Solve for the x intercept; <em>Let y = 0</em>

0 = -\frac{5x}{3} + \frac{8}{3}

Subtract \frac{8}{3} from both sides

0 - \frac{8}{3} = -\frac{5x}{3} + \frac{8}{3} - \frac{8}{3}

- \frac{8}{3} = -\frac{5x}{3}

Subtract both sides by -\frac{3}{5}

-\frac{3}{5}*- \frac{8}{3} = -\frac{5x}{3} * -\frac{3}{5}

-\frac{3}{5}*- \frac{8}{3} = x

\frac{3}{5} * \frac{8}{3} = x

\frac{8}{5} = x

x = \frac{8}{5}

-------------------------------------------------------------------------------------------------------

By comparing the slope, x intercept and y intercept of both lines;

It'll be observed that they have the same slope, x intercept and y intercept

<em>This implies that both lines are equal; in other words, they are the same.</em>

6 0
3 years ago
Factor the polynomial. 7x2 + 68xy - 20y2 A) (7x - 2y)(x + 10y) B) (7x - 10y)(x - 2y) C) (7x + 10y)(x + 2y) D) (7x + 2y)(x - 10y)
Otrada [13]
For this case we have the following polynomial:
 7x2 + 68xy - 20y2
 Factoring we have:
 (7x-2y) (x + 10y)
 We verify the factorization:
 7x2 + 70xy - 2xy - 20y2
 Rewriting we have:
 7x2 + 68xy - 20y2
 Therefore, the factorization is correct.
 Answer:
 
A) (7x - 2y) (x + 10y)
5 0
3 years ago
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