Answer:
This shows 3 pivot position matrixes.
Step-by-step explanation:
The given matrix is:
![\left[\begin{array}{ccc}1&-2&-5\\0&4&3\\-3&3&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%26-5%5C%5C0%264%263%5C%5C-3%263%260%5Cend%7Barray%7D%5Cright%5D)
The option D is correct for this matrix.
The matrix is invertible and the given matrix has 3 pivot positions.
The matrix is invertible if its determinant is nonzero.
Multiply the 3rd row by 1/3.we get:
![\left[\begin{array}{ccc}1&-2&-5\\0&4&3\\-1&1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%26-5%5C%5C0%264%263%5C%5C-1%261%260%5Cend%7Barray%7D%5Cright%5D)
Now, add the first row with third row:
![\left[\begin{array}{ccc}0&-1&-5\\0&4&3\\-1&1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-1%26-5%5C%5C0%264%263%5C%5C-1%261%260%5Cend%7Barray%7D%5Cright%5D)
Replace third row by first row:
![\left[\begin{array}{ccc}-1&1&0\\0&4&3\\0&-1&-5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%261%260%5C%5C0%264%263%5C%5C0%26-1%26-5%5Cend%7Barray%7D%5Cright%5D)
This shows 3 pivot position matrixes.
Hence, a matrix is invertible and has 3 pivot positions.
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
ANSWER
9.5
EXPLANATION
To find the distance between home and work, we have to use the formula:
![D\text{ = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
We have that home is at point (3, -3) and work is at point (0, 6).
Therefore:
(x1, y1) = (3, -3)
(x2, y2) = (0, 6)
Therefore, we have that:
![\begin{gathered} D\text{ = }\sqrt[]{(0-3)^2+(6-(-3))^2} \\ D\text{ = }\sqrt[]{(-3)^2+(6+3)^2}\text{ = }\sqrt[]{(-3)^2+(9)^2} \\ D\text{ = }\sqrt[]{9\text{ + 81}}\text{ = }\sqrt[]{90} \\ D\text{ = 9.5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B%280-3%29%5E2%2B%286-%28-3%29%29%5E2%7D%20%5C%5C%20D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B%28-3%29%5E2%2B%286%2B3%29%5E2%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B%28-3%29%5E2%2B%289%29%5E2%7D%20%5C%5C%20D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B9%5Ctext%7B%20%2B%2081%7D%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B90%7D%20%5C%5C%20D%5Ctext%7B%20%3D%209.5%7D%20%5Cend%7Bgathered%7D)
The answer is 9.5