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vlada-n [284]
3 years ago
14

URGENT PLEASE HELP. A radio signal travels at 3.00 * 10^8 meters per second. how many seconds will it take for a radio signal to

travel from a satellite to the surface of Earth if the satellite is orbiting at a height of 3.54 * 10^7 meters? show all the steps that you used to solve this problem.
Mathematics
2 answers:
lbvjy [14]3 years ago
4 0
So distance=rate x time and if we rearrange this to find the time we get time=distance/rate. Now we can just plug in the numbers.


3.54*10^7/3*10^8=time(seconds)
To solve this we can just divide the parts of the scientific notation separately.

3.54/3=1.18
10^7/10^8=1/10

Now we just multiply our answers together because we separated them before we divided.

1.18*1/10=.118

So the answer is .118 seconds
Rzqust [24]3 years ago
4 0
T = d/s

t = 3.54 x 10.7m / 3 x 10^8 m/s

t= 0.118 s

It would take 0.118 seconds for the radio signal to reach earth
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Answer:

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Step-by-step explanation:

47/100+3/100=50/100 (aka 1/2)

50/100+47/100=97/100

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Which is the simplified form of the expression?
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Given:

Consider the given expression is:

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The simplified form of the given expression.

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We have,

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Using distributive property, it can be written as:

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3 years ago
At which points are the tangents drawn to the ellipse x 2 + y 2 = [ a ] x + [ a ] y parallel to
In-s [12.5K]

The given equation of the ellipse is x^2 + y^2 = 2 x + 2 y

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<span>So we have to take the 1st derivative of the equation then equate dy / dx to zero.</span>

x^2 + y^2 = 2 x + 2 y

x^2 – 2 x = 2 y – y^2

(2x – 2) dx = (2 – 2y) dy

(2x – 2) / (2 – 2y) = 0

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To find for y, we go back to the original equation then substitute the value of x.

x^2 + y^2 = 2 x + 2 y

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y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1

y = 1 ± 2.828

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<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828) and (1, 3.828).</span>

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4 years ago
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AnnyKZ [126]
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x=[-5(+or-)sqrt(5^2-4*1*5)]/(2*1)
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