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vichka [17]
3 years ago
9

Need an answer to this

Mathematics
2 answers:
Firlakuza [10]3 years ago
3 0

Answer:

x=20⁰

Step-by-step explanation:

The angle 6x is next to a 3x one.

And 6x+3x=180⁰

9x=180⁰

x=20⁰

I am Lyosha [343]3 years ago
3 0
X=20 degrees

So that is the answer
You might be interested in
I dentist the slope and a point on the line
Anika [276]

Answer:

2/3 (0,-3) is one possible answer.

Step-by-step explanation:

y  -1 = 2/3(x-6)  We want to get this into the slope intercept form of a line.  We want it to be in the form y = mx + b.  Let's clear the fraction first by multiplying the whole equation through by 3.

3(y - 1) = 3[2/3(x - 6)]

3y -3 = 2(x -6)

3y - 3 = 2x -12

3y = 2x - 9  Now divide all the way through by 3 to get

y = 2/3x - 3  

y = mx + b.  The m part is the slope.  In this equation the slope is 2/3

There are in infinite amount of points on a line.  I do not know if they give you a picture or if you are just to create your own.  I am going to create a point that have x = 0.  I get to pick the point.  I could pick any number.  0 is just usually really easy.  So, if I substitute 0 for x I will get:

y = 2/3(0) - 3

y = 1  so my point is (0,-3)

Now that I think about it, I do not think that I would start out clearing the fraction even though it works.  I think that I would do it like this"

y - 1 = 2/3(x - 6)  Distribute the 2/3 through (x - 4) to get

y-1 = 2/3x -4  I can make -6 a fraction by putting it over 1.  Now we have 2/3(-6/1)  multiply across to get  -12/3.  A positive times a negative is a negative.  -12 divided by 3 is -4.

y - 1 = 2/3x -4   now add 1 to both sides.

y = 2/3x -3

6 0
1 year ago
A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In
lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

                        P.Q. = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of males having blood disorder= \frac{250}{1000} = 0.25

\hat p_2 = sample proportion of females having blood disorder = \frac{275}{1000} = 0.275

n_1 = sample of males = 1000

n_2 = sample of females = 1000

p_1 = population proportion of males having blood disorder

p_2 = population proportion of females having blood disorder

<em>Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.</em>

<u>So, 95% confidence interval for the difference between the population proportions, </u><u>(</u>p_1-p_2<u>)</u><u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                             of significance are -1.96 & 1.96}  

P(-1.96 < \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < {(\hat p_1-\hat p_2)-(p_1-p_2)} < 1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

P( (\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < (p_1-p_2) < (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

<u>95% confidence interval for</u> (p_1-p_2) =

[(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }, (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }]

= [ (0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }, (0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} } ]

 = [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0
3 years ago
The owner of the Rancho Grande has 3,044 yd of fencing with which to enclose a rectangular piece of grazing land situated along
inysia [295]

Answer:

Step-by-step explanation:

Area of the rectangular piece A = xy

x is the length

y is the width

Perimeter =2x+2y

Given

Perimeter = 3044yds

3044 = 2x+2y

1522 = x+y

x = 1522-y

Substitute into the formula for area

A = xy

A = (1522-y)y

A = 1522y-y²

To maximize the area, dA/dy must be zero

dA/dy = 1522-2y

0 = 1522-2y

2y = 1522

y = 1522/2

y = 761

Since x+y = 1522

X+761 = 1522

X = 761

Dimension is 761yd by 761yd

Area = 761×761 = 579121yd²

7 0
3 years ago
If u = 8 + 4i and v = 3i + 6, then what is u – v?
lozanna [386]
u=8+4i\ and\ v=31+6\\\\u-v=(8+4i)-(3i+6)=8+4i-3i-6=(8-6)+(4i-3i)\\\\\huge\boxed{=2+i}\leftarrow \boxed{d}
7 0
3 years ago
Can someone help me please and thanks .
enyata [817]

Answer:

<em>$180.</em>

Step-by-step explanation:

First lets find the <em>interest rate.</em>

<em>6.1 ÷ 100 = 0.061</em>

<em>0.061 x $200 = 12.2</em>

based on the calculations, <em>12.2</em> is our interest rate <em>in a year</em>.  Now lets find the interest rate in <em>15 years</em>.

<em>12.2 x 15 = $183 </em>

So <em>$183</em> is our<em> precise</em> interest rate in <em>15 years</em>, but lets<em> round the interest rate to the nearest 10 dollars.</em>  Therefore, <em>$180 is our answer.</em>

6 0
3 years ago
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