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yKpoI14uk [10]
3 years ago
15

8 weeks is what percent of a year?

Mathematics
2 answers:
emmasim [6.3K]3 years ago
7 0

There's approx. 52 week in a year, so 8 weeks is approx. 15.38%

Montano1993 [528]3 years ago
5 0

There are 52 weeks in a year;

create a fraction

8/52

solve:

0.1538

create a percentage:

15.38%

Hope I helped...

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Ganezh [65]

Answer:

Here

Step-by-step explanation:

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Range : (-∞,∞)
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2 years ago
A printer toner company launches a new product. The number of pages that this new toner can print is normally distributed with a
Vitek1552 [10]

Answer:

Step-by-step explanation:

Since the number of pages that this new toner can print is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = the number of pages.

µ = mean

σ = standard deviation

From the information given,

µ = 2300 pages

σ = 150 pages

1)

the probability that this toner can print more than 2100 pages is expressed as

P(x > 2100) = 1 - P(x ≤ 2100)

For x = 2100,

z = (2100 - 2300)/150 = - 1.33

Looking at the normal distribution table, the probability corresponding to the z score is 0.092

P(x > 2100) = 1 - 0.092 = 0.908

2) P(x < 2200)

z = (x - µ)/σ/√n

n = 10

z = (2200 - 2300)/150/√10

z = - 100/47.43 = - 2.12

Looking at the normal distribution table, the probability corresponding to the z score is 0.017

P(x < 2200) = 0.017

3) for underperforming toners, the z score corresponding to the probability value of 3%(0.03) is

- 1.88

Therefore,

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4 0
3 years ago
Questions 16-17 | Math 1 - 0 points Solve the graph Help needed !!
iris [78.8K]

Answer:

16) The area of the circle is 25.1 units²

17) JKLM is a parallelogram but not a rectangle

Step-by-step explanation:

16) Lets talk about the area of the circle

- To find the area of the circle you must find the length of the radius

- In the problem you have the center of the circle and a point on

 the circle, so you can find the length of the radius by using the

 distance rule

* Lets solve the problem

∵ The center of the circle is (1 , 3)

∵ The point on the circle is (3 , 5)

- Using the rule of the distance between two points

* Lets revise it

- The distance between the two points (x1 , y1) and (x2 , y2) is:

 Distance = √[(x2 - x1)² + (y2 - y1)²]

∴ r = √[(3 - 1)² + (5 - 3)²] = √[4 + 4] = √8 = 2√2 units

∵ The area of the circle = πr²

∴ The area of the circle = π (2√2)² = 8π = 25.1 units²

* The area of the circle is 25.1 units²

17) To prove a quadrilateral is a parallelogram, prove that every

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* The parallelogram can be rectangle if two adjacent sides are

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- The parallel lines have equal slopes, then to prove the

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* Lets find from the graph the vertices of the quadrilateral

∵ J = (0 ,2) , K (2 , 5) , L (5 , 0) , M (3 , -3)

- The opposite sides are JK , ML and JM , KL

- The slope of any line passing through point (x1 , y1) and (x2 , y2) is

 m = (y2 - y1)/(x2 - x1)

∵ The slop of JK = (5 - 2)/(2 - 0) = 3/2 ⇒ (1)

∵ The slope of LM = (-3 - 0)/(3 - 5)= -3/-2 = 3/2 ⇒ (2)

- From (1) and (2)

∴ JK // LM

∵ The slope of KL = (0 - 5)/(5 - 2) = -5/3 ⇒ (3)

∵ The slope of JM = (-3 - 2)/(3 - 0)= -5/3 ⇒ (4)

- From (3) and (4)

∴ KL // JM

∵ Each two opposite sides are parallel in the quadrilateral JKLM

∴ It is a parallelogram

- The product of the slopes of the perpendicular line is -1

* lets check the slopes of two adjacent sides in the JKLM

∵ The slope of JK = 3/2 and the slope of KL = -5/3

∵ 3/2 × -5/3 = -5/2 ≠ -1

∴ JKLM is a parallelogram but not a rectangle

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blondinia [14]

Answer:

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1 year ago
John wants to invite around 78,000 college students to a tournament. Which of the following sets of college student populations
Ad libitum [116K]

Answer:

a

Step-by-step explanation:

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