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bija089 [108]
3 years ago
11

Which of the following expressions are equivalent to c/d? Choose all answers that apply:

Mathematics
1 answer:
andrezito [222]3 years ago
5 0

Answer:

Both A and B are correct because a negative divided by a negative makes a positive.

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Step-by-step explanation:

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29x97 broken apart <br> need help now <br> Factors willl mark brainlyest
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I don't know what you mean by "Broken apart," but I'll do my best...

20 x 90 = 1800

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notka56 [123]

Answer:

=

Step-by-step explanation:

lcm = 8 so you multiply the numerator of 2 1/2    1 x 4 = 4  4 is your numerator and 8 is your denominator        2 4/8 = 2 4/8 you can simplify to 2 1/2 too

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2 years ago
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Figure 6 shows a semicircle PTS with center O and radius 8cm. QST is a sector of a circle with center S and R is the midpoint of
sveticcg [70]

(a) <TOR=pi/3 radians

To determine <TOR we use the fact that in the right-angled triangle ORT we know two sides:

|OT|=radius=8cm and |OR|=radius/2=4cm

and can use the sine:

\sin \angle OTR=\frac{r/2}{r}=\frac{1}{2}\implies \angle OTR =\frac{\pi}{6}

and since <TRO=pi/2, it must be that

\angle TOR =\pi-\frac{\pi}{2}-\frac{\pi}{6}=\frac{\pi}{3}

(b) The arc length is approximately 7.255 cm

In order to calculate the arc length QT, we need to first determine the length |ST| and the angle <OST.

Towards determining angle <OST:

\angle SOT = \pi - \angle TOR = \pi - \frac{\pi}{3} = \frac{2}{3}\pi

Next, draw a line connecting P and T. Realize that triangle PTS is right-angled with <PTS=pi/2. This follows from the Thales theorem. Since R is a midpoint between P and O, it follows that the triangles ORT and PRT are congruent. So the angles <PTR and <OTR are congruent. Knowing <PTS we can  determine angle <OTS:

\angle OTR \cong \angle PTR=\frac{\pi}{6}\implies\angle OTS=\angle PTS -\angle PTR -\angle OTR\\\angle OTS = \frac{\pi}{2}-\frac{\pi}{6}-\frac{\pi}{6}=\frac{\pi}{6}

and so the angle <OST is

\angle OST = \pi - \angle TOS - \angle OTS = \pi -\frac{2}{3}\pi - \frac{1}{6}\pi=\frac{\pi}{6}

Towards determining |TS|:

Use cosine:

\cos \angle OST =\frac{|RS|}{|ST|}\implies |ST|=\frac{\frac{3}{2}r}{\cos \frac{\pi}{6}}=\frac{12\cdot 2}{\sqrt{3}}=8\sqrt{3}cm

Finally, we can determine the arc length QT:

QT = {\angle OST}\cdot |ST|=\frac{\pi}{6}\cdot 8 \sqrt{3}=\frac{4\pi}{\sqrt{3}}\approx 7.255cm




3 0
3 years ago
Daniel is very extraverted.He admits that he is not comfortable unless surrounded by other people,and he energetically pursues a
viktelen [127]

Answer:

A is the most likely answer

Step-by-step explanation:

but how is this a math question?

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