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kap26 [50]
3 years ago
14

Which of the following function is graphed?

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
4 0

Answer:

D

Step-by-step explanation:

Try to remember this formula.

y=a|b(x-c)|+d

Where a is the vertical multiplier, b is the horizontal multiplier, c is the x coordinate of the vertex, and d is the y coordinate of the vertex.

Since the vertex on the graph is (2,3), c and d have to be 2 and 3.

Also, there are no vertical/horizontal stretches so the a and b values stay at 1.

The final equation would come out to y=|x-2|+3

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Number between 61 and 107 that is multiple of 2,6 and 8
mariarad [96]
Not saying my answer is 100% correct but I quickly tried to solve this and got 72.
(2x36, 6x12, 8x9)
3 0
3 years ago
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Can anyone help with this. Will give you all my points and brainliest:)
Nana76 [90]

Answer:3. 4:8

4. 1:4

Step-by-step explanation:

5. 48

6. 3

4 0
3 years ago
Can someone please help me with this? It would be greatly appreciated:) thanks
kati45 [8]

Answer:

d < 1

Step-by-step explanation:

First, we have to get d on the same side of the equation. So we will subtract d from both sides and the equation will be  12d-d < + 11. We could also write this problem as d(12-1) < 11, which when simplified would be d(11) < 11. Next, divide both sides by 11 and you get d< 1.   Hope this helps and have a great day!!:D

3 0
3 years ago
Write at least 5 arithmetic sequence and determine the common difference
Margarita [4]

Answer: 1,6,11,16,21,26

Step-by-step explanation:

The common difference is 5 (n+5)

7 0
3 years ago
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If a triangle has side lengths 7, 10, and 12, is it a right triangle??
Vesnalui [34]

Answer:

No. Remember, a right angle must have a 90 degree angle. We can find the lengths with the Pythagorean Theorem.

Step-by-step explanation:

Given the length 7, 10, and 12, we can assume that 12 is the hypotenuse (it is the longest length).

- we can use 7 and 10 interchangeably.

Fill in the equation, a^2 + b^2 = c^2

                 where c = 12, and a or b = 7 or 10.

To indicate if the given lengths would form a right angle, we can only input 7 or 10, not both.

Therefore, 7^2 + b^2 = 12^2 or 10^2 + b^2 = 12^2

7^2 + b^2 = 12^2 ==> 49 + b^2 = 144 ==> <u>b= </u>\sqrt{95<u> ==> </u><u>9.746</u>

b= 9.7, not 10.

10^2 + b^2 = 12^2 ==> 100 + b^2 = 144 ==> <u>b = </u>\sqrt{44<u> ==> </u><u>6.633 </u>

b= 6.6, not 7.

Therefore, the lengths 7, 10, and 12, does NOT make a right triangle.

Hope this helps!

5 0
3 years ago
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